Assume that a procedure yields a binomial distribution with n=1222n=1222 trials and the probability of success for one trial is p=38%p=38%.Find the mean for this binomial distribution.(Round answer to one decimal place.)μ=μ= Find the standard deviation for this distribution.(Round answer to two decimal places.)σ=σ= Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers.usual values =

Question
Asked Nov 2, 2019

Assume that a procedure yields a binomial distribution with n=1222n=1222 trials and the probability of success for one trial is p=38%p=38%.

Find the mean for this binomial distribution.
(Round answer to one decimal place.)
μ=μ= 

Find the standard deviation for this distribution.
(Round answer to two decimal places.)
σ=σ= 

Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.
Enter answer as an interval using square-brackets only with whole numbers.
usual values = 

 

check_circleExpert Solution
Step 1

It is given that the random variable X follows a binomial distribution with n=1,222 and p=0.38.

The mean of binomial random variable is given and calculated as follows:

(1,222)(0.38)
= 464.36
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(1,222)(0.38) = 464.36

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Step 2

The standard deviation of binomial random varia...

fnp(1-p)
(1,222)(0.38) (1-0.38)
287.9
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fnp(1-p) (1,222)(0.38) (1-0.38) 287.9

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