Assume that a procedure yields a binomial distribution with n=1222n=1222 trials and the probability of success for one trial is p=38%p=38%.
Find the mean for this binomial distribution.
(Round answer to one decimal place.)
μ=μ=
Find the standard deviation for this distribution.
(Round answer to two decimal places.)
σ=σ=
Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.
Enter answer as an interval using square-brackets only with whole numbers.
usual values =
Find answers to questions asked by students like you.
Q: If n = 20 and p = 0.90, then the standard deviation of the binomial distribution is
A: Given: n= 20 p=0.90
Q: Find the standard deviation for n = 300 and p = 0.3 when the conditions for the binomial…
A: According to the provided information, n = 300 p = 0.3
Q: If x=26,412 tuition per a four year and n=7,498 is standard deviation. Assuming the distribution is…
A: From the provided information, Mean (µ) = 26412 Standard deviation (σ) = 7498 X ~N (26412, 7498)
Q: A normally distributed population with 200 elements has a mean of 60 and a standard deviation of 10.…
A: Click to see the answer
Q: If n=10 and p=0.8, then the standard deviation of the binomial distribution is
A: We have given that, Let x be the random variable with n = 10 and P = 0.8 from the binomial…
Q: If we know that the length of time it takes a college student to find a parking spot in the library…
A: Normal distribution is a continuous distribution which has many real life applications. Normal curve…
Q: Find the mean of a binomial distribution when q = 14% and n = 202. ? = b.Find the standard…
A: Click to see the answer
Q: Assume that the heights of men are normally distributed with a mean of 67.2 inches and a standard…
A: Click to see the answer
Q: Assume that a procedure yields a binomial distribution. n = 43 p = 0.7, Find the standard…
A: Solution for given problem is as follows,
Q: The expected (mean) life of a particular type of light bulb is 1,000 hours with a standard deviation…
A: Given Mean = 1000 hrs Standard deviation = 50 hrs To calculate probability for X > 1150 hrs
Q: 20% of the students in a class of 400 are planning to go to graduate school. The standard deviation…
A: Click to see the answer
Q: Assume that a procedure yields a binomial distribution with n=1421 trials and the probability of…
A: Solution
Q: If n = 15 and p = .4, then the standard deviation of the binomial distribution is
A: Obtain the standard deviation of the binomial distribution. The standard deviation of the binomial…
Q: Assume that the heights of men are normally distributed with a mean of 69.0 inches and a standard…
A: According to the given information, we have Mean = 69.0 Standard deviation = 2.8 Sample size = 64
Q: t a company manufactures is 5 years, or 60 months, and the standard deviation is 8 months. Find the…
A: Let X be the random variable such lifetime of smoke detectors that a company manufactures in months.…
Q: For a binomial distribution with n = 15 and p = 0.2, what is the standard deviation of the…
A: Click to see the answer
Q: Find the standard deviation, σ, for the binomial distribution which has n = 48 and p = 3/5. Round…
A: Let "X" be the binomial random variable.
Q: Find the standard deviation, σ, for the binomial distribution which has n = 48 and p = 3/5. Round…
A: Given: n = 48 p=35
Q: A. C. Neilsen reported that children between the ages of 2 and 5 watch an average of 25 hours of…
A: Let x be the number of hours ages of 2 and 5 watch television which follows normal distribution with…
Q: To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees…
A: Click to see the answer
Q: For the binomial distribution, which formula finds the standard deviation? Choose the correct answer…
A: we know that For binomial distribution MEAN = μ=n ×p VARIANCE = δ2 =n x p x q STANDARD DEVIATION =…
Q: A population has a mean of 200 and a standard deviation of 50. Suppose a simple random sample of…
A: Given,Population mean (μ) = 200Population standard deviation (σ) = 50Sample size (n) = 100.We know…
Q: Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean…
A: From the provided information, Mean (µ) = 0oC Standard deviation (σ) = 1.00oC X~N (0, 1) Here X be a…
Q: Ex: an electronics company manufactures resistors that have a mean resistance of 95 ohms and a…
A: Click to see the answer
Q: Find the mean and variance from the m. g. f.of binomial distribution.
A: Click to see the answer
Q: Find the mean and variance from the m. g.f.of binomial distribution.
A: Click to see the answer
Q: a population has a normal distribution with a mean of 50 and a stadnard deviation of 10. if a random…
A: Given,mean(μ)=50standard deviation(σ)=10sample size(n)=9
Q: Suppose the daily demand for petrol at a certain petrol station is nomally distributed with a mean…
A: Given, mean (µ ) = 6849 standard deviation (σ) = 342 Let 'X' be a random variable,X ~ N ( µ = 6849…
Q: The distribution of weekly salaries at a large company has a mean of $1000 and a standard deviation…
A: Given Mean=1000 Standard deviation=350 N=50
Q: In a certain state, the daily amounts of industrial waste are normally distributed with a mean of…
A: Let us denote X=the daily amounts of industrial wasteGiven that X is normally distributed with…
Q: Assume that women's weights are normally distributed with a mean given by μ=143lb and a standard…
A: Click to see the answer
Q: The average student loan debt for college graduates is $25,650. Suppose that that distribution is…
A: Given: Mean, μ= 25650 Standard deviation, σ= 14350 (b) Probability that college graduates has…
Q: The average student loan debt for college graduates is $25,600. Suppose that that distribution is…
A: Click to see the answer
Q: In a two - tailed test, given that the population mean is 40 with a standard deviation of 2.5. A…
A: Click to see the answer
Q: A population has a mean of 60 and a standard deviation of 18. A sample of 81 observations will be…
A: Click to see the answer
Q: Find the standard deviation,σ,for the binomial distribution which has the stated values of n and…
A: Given: n=503p=0.7⇒q=1-p=1-0.7q=0.3 The standard deviation calculates as follows:…
Q: The manager of a computer help desk operation has collected enough data to conclude that the…
A: Given, Mean = μ = 8.21 Standard deviation = σ = 2.14 Sample size = n = 40 The x is normally…
Q: Suppose a mutual fund qualifies as having moderate risk if the standard deviation of its monthly…
A: Given that, Consider σ is the population standard deviation, s is the sample standard deviation n is…
Q: Suppose a mutual fund qualifies as having moderate risk if the standard deviation of its monthly…
A: State the hypotheses. That is, there is no evidence that the true standard deviation of its monthly…
Q: Assume that a procedure yields a binomial distribution with n = 675 trials and the probability of…
A: The mean for the binomial distribution is obtained below: From the given information, the number of…
Q: Find the standard deviation, σ, for the binomial distribution which has the stated values of n and…
A: n = 48; p = 3/5 X ~ N(n, p) Standard deviation = npq = 48×35×25…
Q: Assume that a population is normally distributed with a mean of 100 and a standard deviation of 15.…
A: Since the area corresponding to z-value 1.73205 is 0.958368 calculated by Excel command NORM.S.DIST…
Q: Given a normally distributed random variable with a mean of 196 and a standard deviation of 20, find…
A: In this context, it is given that X follows normal distribution with a mean of 196 and a standard…
Q: A leading magazine reported at one time that the average number of weeks an individual is unemployed…
A: μ=18.7 weeksσ=9.1 weeksn = 210
Q: A recent analysis of the number of rainy days per month found the following outcomes and…
A: Solution x P(x) x*P(x) x2 x2*P(x) 3 0.4 1.2 9 3.6 4 0.2 0.8 16 3.2 5 0.4 2 25 10
Q: A company produces tortillas that are supposed to have an average diameter of 6 inches. Each of the…
A: Given that a company produces tortillas that are supposed to have an average diameter of 6 inches.…
Q: Assume that the heights of women are normaly distributed with a mean of 63.6 inches and a standard…
A: Given, Mean = 63.6 Standard deviation = 2.5 Sample size = 100 The objective is to find the…
Q: The mean weight of junior high school students is µ = 45 kg. If a random sample of 90 students is…
A: Given: μ=45n=90σ=6
Q: While checking receipts at The Hog Cafe, it was determined that the average amount spent on food per…
A: Given that, Let X be the random variable from normal distribution with average or mean (μ) = $21.50…
Q: For a binomial distribution, the mean is 6 and the standard deviation is 2. Write out all the terms…
A: Click to see the answer