Assume that a procedure yields a binomial distribution with n=6 trials and a probability of success of p=0.10. Use a binomial probability table to find the probability that the number of successes x is exactly 3.
Assume that a procedure yields a binomial distribution with n=6 trials and a probability of success of p=0.10. Use a binomial probability table to find the probability that the number of successes x is exactly 3.
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 33E: Sick leave probability that a given worker at Dyno Nutrition Will call in sick on a Monday is 004....
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Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Question
Assume that a procedure yields a binomial distribution with n=6 trials and a probability of success of p=0.10. Use a binomial probability table to find the probability that the number of successes x is exactly 3.
Transcribed Image Text:Binomial Probabilities
01
.05
10
.20
.30
.40
.50
60
.70
80
.90
.95
.99
2
.980
.902
.810
.640
.490
.360
.250
.160
090
040
010
002
0+
2
1
020
.095
.180
.320
.420
.480
.500
480
420
320
.180
095
.020
1
0+
.002
.010
.040
.090
.160
.250
360
490
640
810
902
.980
2
3
970
857
729
.512
.343
216
.125
064
027
005
001
0+
0+
3
1
029
.135
243
.384
.441
.432
.375
268
.189
096
027
007
0+
1
2
0+
.007
.027
.096
.189
.288
375
432
441
384
243
.135
.029
2
3
0+
0+
.001
.008
.027
.064
.125
216
343
512
.729
857
.970
3
4
951
.815
.656
410
.240
.130
.062
026
008
002
0+
0+
0+
1
039
.171
.292
410
.412
.346
.250
.154
076
026
004
0+
0+
1
2
001
.014
.049
.154
.265
.346
.375
346
265
.154
049
014
.001
3
0+
0+
.004
.026
.076
.154
.250
346
412
410
292
.171
.039
3
4.
0+
0+
0+
.002
.008
.026
.062
.130
240
410
656
815
.961
4.
5
951
.774
.590
.326
.168
.078
.031
010
002
0+
0+
0+
0+
5
1
048
.204
.328
410
.360
.259
.156
077
028
006
0+
0+
0+
1
001
.021
.073
.205
.309
.346
.312
230
.132
051
005
001
0+
2
3
0+
.001
.008
.051
.132
230
312
346
309
205
073
021
.001
3
4
0+
0+
0+
.006
.028
.077
.156
259
360
410
328
204
.048
4.
0+
0+
0+
0+
.00e
.010
.031
078
.168
328
590
.774
.951
941
.735
.531
.262
.118
.047
.016
004
001
0+
0+
0+
0+
6
1
057
.232
.354
.393
.303
.187
.094
037
010
002
0+
0+
0+
1
2
001
.031
.098
246
.324
.311
.234
.138
060
015
001
0+
0+
2
3
0+
.002
015
082
.185
276
312
276
.185
082
015
002
0+
3
4
0+
0+
.001
.015
.060
.138
.234
311
324
246
095
031
.001
5
0+
0+
0+
.002
.010
.037
.094
.187
303
393
354
232
.057
5
6
0+
0+
0+
0+
.001
.004
.016
047
.118
262
531
.735
.941
7
932
.698
478
.210
.082
.c28
.008
002
0+
0+
0+
0+
0+
1
066
.257
372
.367
.247
.131
.055
017
004
0+
0+
0+
0+
1
2
002
.041
.124
275
.318
.261
.164
077
025
004
0+
0+
0+
2
3
0+
.004
.023
.115
.227
.290
273
194
097
029
003
0+
0+
3
0+
0+
.003
.029
097
194
.273
290
227
.115
023
004
0+
4
0+
0+
0+
.004
.025
.077
.164
261
318
275
.124
041
.002
5
6
0+
0+
0+
0+
.004
.017
.065
.131
247
367
372
257
.066
6
0+
0+
0+
0+
0+
.00e
.008
028
082
210
478
698
.932
7
8
923
.663
430
.168
.058
.017
.004
001
0+
0+
0+
0+
0+
8
1
075
.279
.383
.336
.198
.090
.031
008
001
0+
0+
0+
0+
1
2
.003
.051
149
294
.296
.209
.109
041
010
001
0+
0+
0+
3
0+
.005
.033
.147
.254
.279
.219
.124
047
009
0+
0+
0+
3
4
0+
0+
.005
.046
.136
.232
.273
232
.136
046
005
0+
0+
5
0+
0+
0+
.009
.047
124
.219
279
254
.147
033
005
0+
5
0+
0+
0+
.001
.010
.041
.109
209
296
294
.149
051
.003
6
0+
0+
0+
0+
.001
.008
.031
.090
.198
336
383
279
.075
7
8
0+
0+
0+
0+
0+
.001
.004
017
058
.168
430
.663
.923
01
.05
.10
.20
.30
.40
.50
60
70
80
.90
95
.99
NOTE 0+ represents a positive probebilty less than 0.0005.
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