Question

Asked Nov 19, 2019

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Assume that a sample is used to estimate a population proportion *p*. Find the 99% confidence interval for a sample of size 216 with 76% successes. Enter your answer as an **open-interval** (*i.e.*, parentheses) using decimals (not percents) accurate to three decimal places.

C.I. =

Step 1

**Introduction:**

The 100 (1 – *α*) % confidence interval for the population proportion, *p* is: (*p̂ *– (*zα*/2) *√*(*p* (1 – *p*)/*n*), *p̂ *+ (*zα*/2) *√*(*p* (1 – *p*)/*n*)).

Here, *n* is the sample size, *p̂* is the sample proportion, and *zα*/2 is the critical value of the *z*-distribution, above which, 100 (...

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