Assume that military aircraft use ejection seats designed for men weighing between 141.2 lb and 202 lb. If women's weights are normally distributed with a mean of 172.6 lb and a standard deviation of 45.9 lb, what percentage of women have weights that are within those limits? Are many women excluded with those specifications? The percentage of women that have weights between those limits is 49.21 %. (Round to two decimal places as needed.) Are many women excluded with those specifications? A. Yes, the percentage of women who are excluded, which is the complement of the probability found previously, shows that about half of women are excluded. B. Yes, the percentage of women who are excluded, which is equal to the probability found previously, shows that about half of women are excluded. C. No, the percentage of women who are excluded, which is the complement of the probability found previously, shows that very few women are excluded. D. No, the percentage of women who are excluded, which is equal to the probability found previously, shows that very few women are excluded. 9:18 1 ME = 172.6, TF=45.9 F→ Female; =P/ 141-2-172.6 X-ME < 202-172-6 :45-9 (या P(-0.6841 < z <0.6405) P(Z

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Assume that military aircraft use ejection seats designed for men weighing between 141.2 lb and 202 lb. If women's weights are normally distributed with a mean of 172.6 lb and a standard deviation of 45.9 lb, what
percentage of women have weights that are within those limits? Are many women excluded with those specifications?
The percentage of women that have weights between those limits is 49.21 %.
(Round to two decimal places as needed.)
Are many women excluded with those specifications?
A. Yes, the percentage of women who are excluded, which is the complement of the probability found previously, shows that about half of women are excluded.
B. Yes, the percentage of women who are excluded, which is equal to the probability found previously, shows that about half of women are excluded.
C. No, the percentage of women who are excluded, which is the complement of the probability found previously, shows that very few women are excluded.
D. No, the percentage of women who are excluded, which is equal to the probability found previously, shows that very few women are excluded.
Transcribed Image Text:Assume that military aircraft use ejection seats designed for men weighing between 141.2 lb and 202 lb. If women's weights are normally distributed with a mean of 172.6 lb and a standard deviation of 45.9 lb, what percentage of women have weights that are within those limits? Are many women excluded with those specifications? The percentage of women that have weights between those limits is 49.21 %. (Round to two decimal places as needed.) Are many women excluded with those specifications? A. Yes, the percentage of women who are excluded, which is the complement of the probability found previously, shows that about half of women are excluded. B. Yes, the percentage of women who are excluded, which is equal to the probability found previously, shows that about half of women are excluded. C. No, the percentage of women who are excluded, which is the complement of the probability found previously, shows that very few women are excluded. D. No, the percentage of women who are excluded, which is equal to the probability found previously, shows that very few women are excluded.
9:18 1
ME = 172.6, TF=45.9
F→ Female;
=P/ 141-2-172.6 X-ME < 202-172-6
:45-9
(या
P(-0.6841 < z <0.6405)
P(Z<O:6405) -P(ZE =O.684))
%3D
6.7391-O•2470
0.4921
49.21%0
as
100-49.2| = 50.79 %,
excluded with those specificationy
so, optiom A|.
blease Rate!!
any doubts please ask ! thank you :))
Transcribed Image Text:9:18 1 ME = 172.6, TF=45.9 F→ Female; =P/ 141-2-172.6 X-ME < 202-172-6 :45-9 (या P(-0.6841 < z <0.6405) P(Z<O:6405) -P(ZE =O.684)) %3D 6.7391-O•2470 0.4921 49.21%0 as 100-49.2| = 50.79 %, excluded with those specificationy so, optiom A|. blease Rate!! any doubts please ask ! thank you :))
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