Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2 3 4 5 6 7 8 Upper X Subscript iXi 52.152.1 47.447.4 47.647.6 47.347.3 47.347.3 47.447.4 48.848.8 49.249.2 Upper Y Subscript iYi 53.953.9 48.148.1 49.749.7 51.251.2 48.548.5 49.849.8 52.152.1 48.448.4 (a) Determine d Subscript i Baseline equals Upper X Subscript i Baseline minus Upper Y Subscript idi=Xi−Yi for each pair of data. Observation 1 2 3 4 5 6 7 8 di negative −1.8 negative −0.7 negative −2.1 negative −3.9 negative −1.2 negative −2.4 negative −3.3 0.8 (Type integers or decimals.) (b) Compute d overbard and s Subscript dsd. d overbardequals=negative 1.825 (Round to three decimal places as needed.) s Subscript dsdequals=1.485 (Round to three decimal places as needed.) (c) Test if mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. What are the correct null and alternative hypotheses? A. Upper H 0H0: mu Subscript dμdgreater than>0 Upper H 1H1: mu Subscript dμdless than<0 B. Upper H 0H0: mu Subscript dμdequals=0 Upper H 1H1: mu Subscript dμdless than<0 Your answer is correct. C. Upper H 0H0: mu Subscript dμdless than<0 Upper H 1H1: mu Subscript dμdequals=0 D. Upper H 0H0: mu Subscript dμdless than<0 Upper H 1H1: mu Subscript dμdgreater than>0 P-valueequals=0.0050.005 (Round to three decimal places as needed.) Choose the correct conclusion below. A. Do not rejectDo not reject the null hypothesis. There is insufficientinsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. B. RejectReject the null hypothesis. There is insufficientinsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. C. Do not rejectDo not reject the null hypothesis. There is sufficientsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. D. RejectReject the null hypothesis. There is sufficientsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. Your answer is correct. (d) Compute a 95% confidence interval about the population mean difference mu Subscript dμd. The lower bound is nothing. The upper bound is nothing. (Round to two decimal places as needed.)

Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2 3 4 5 6 7 8 Upper X Subscript iXi 52.152.1 47.447.4 47.647.6 47.347.3 47.347.3 47.447.4 48.848.8 49.249.2 Upper Y Subscript iYi 53.953.9 48.148.1 49.749.7 51.251.2 48.548.5 49.849.8 52.152.1 48.448.4 (a) Determine d Subscript i Baseline equals Upper X Subscript i Baseline minus Upper Y Subscript idi=Xi−Yi for each pair of data. Observation 1 2 3 4 5 6 7 8 di negative −1.8 negative −0.7 negative −2.1 negative −3.9 negative −1.2 negative −2.4 negative −3.3 0.8 (Type integers or decimals.) (b) Compute d overbard and s Subscript dsd. d overbardequals=negative 1.825 (Round to three decimal places as needed.) s Subscript dsdequals=1.485 (Round to three decimal places as needed.) (c) Test if mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. What are the correct null and alternative hypotheses? A. Upper H 0H0: mu Subscript dμdgreater than>0 Upper H 1H1: mu Subscript dμdless than<0 B. Upper H 0H0: mu Subscript dμdequals=0 Upper H 1H1: mu Subscript dμdless than<0 Your answer is correct. C. Upper H 0H0: mu Subscript dμdless than<0 Upper H 1H1: mu Subscript dμdequals=0 D. Upper H 0H0: mu Subscript dμdless than<0 Upper H 1H1: mu Subscript dμdgreater than>0 P-valueequals=0.0050.005 (Round to three decimal places as needed.) Choose the correct conclusion below. A. Do not rejectDo not reject the null hypothesis. There is insufficientinsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. B. RejectReject the null hypothesis. There is insufficientinsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. C. Do not rejectDo not reject the null hypothesis. There is sufficientsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. D. RejectReject the null hypothesis. There is sufficientsufficient evidence that mu Subscript dμdless than<0 at the alphaαequals=0.05 level of significance. Your answer is correct. (d) Compute a 95% confidence interval about the population mean difference mu Subscript dμd. The lower bound is nothing. The upper bound is nothing. (Round to two decimal places as needed.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.4: Distributions Of Data

Problem 22PFA

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Question

Assume that the differences are normally distributed. Complete parts (a) through (d) below.

Observation	1	2	3	4	5	6	7	8
Upper X Subscript iXi	52.152.1	47.447.4	47.647.6	47.347.3	47.347.3	47.447.4	48.848.8	49.249.2
Upper Y Subscript iYi	53.953.9	48.148.1	49.749.7	51.251.2	48.548.5	49.849.8	52.152.1	48.448.4

(a) Determine

d Subscript i Baseline equals Upper X Subscript i Baseline minus Upper Y Subscript idi=Xi−Yi

for each pair of data.

Observation	1	2	3	4	5	6	7	8
di	negative −1.8	negative −0.7	negative −2.1	negative −3.9	negative −1.2	negative −2.4	negative −3.3	0.8

(Type integers or decimals.)

(b) Compute

d overbard

and

s Subscript dsd.

d overbardequals=negative 1.825

(Round to three decimal places as needed.)

s Subscript dsdequals=1.485

(Round to three decimal places as needed.)

mu Subscript dμdless than<0

at the

alphaαequals=0.05

level of significance.

What are the correct null and alternative hypotheses?

Upper H 0H0:

mu Subscript dμdgreater than>0

Upper H 1H1:

mu Subscript dμdless than<0

Upper H 0H0:

mu Subscript dμdequals=0

Upper H 1H1:

mu Subscript dμdless than<0

Your answer is correct.

Upper H 0H0:

mu Subscript dμdless than<0

Upper H 1H1:

mu Subscript dμdequals=0

Upper H 0H0:

mu Subscript dμdless than<0

Upper H 1H1:

mu Subscript dμdgreater than>0

P-valueequals=0.0050.005

(Round to three decimal places as needed.)

Choose the correct conclusion below.

Do not rejectDo not reject

the null hypothesis. There is

insufficientinsufficient

evidence that

mu Subscript dμdless than<0

at the

alphaαequals=0.05

level of significance.

RejectReject

the null hypothesis. There is

insufficientinsufficient

evidence that

mu Subscript dμdless than<0

at the

alphaαequals=0.05

level of significance.

Do not rejectDo not reject

the null hypothesis. There is

sufficientsufficient

evidence that

mu Subscript dμdless than<0

at the

alphaαequals=0.05

level of significance.

RejectReject

the null hypothesis. There is

sufficientsufficient

evidence that

mu Subscript dμdless than<0

at the

alphaαequals=0.05

level of significance.

Your answer is correct.

(d) Compute a 95% confidence interval about the population mean difference

mu Subscript dμd.

The lower bound is

nothing.

The upper bound is

nothing.

(Round to two decimal places as needed.)

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