Assume that the distribution of heights of young women aged 16 to 22 is approximately Nomal with mean u = 62.05 inches. A random sample of 73 female undergraduate students at a University produced a sample mean height of can be derved from the adjacent chart. SHOW YOUR FORMULAS AND ALL WORK ON THIS PAGE a) Using the data set, perfom an analysis to detemine the below. Assume the Standard Deviation for the Sample is the same as the Standard Deviation of the Population: Mean Standard Deviation Standard Eror 62.65753425 2.95906882 0.346332809 Explain the difference between the Stardard Deviation and Standard Eror The standard deviation measurethe amount of dispersion from the individual data while the standard errar of the mean measure how the mean of the data is likaly to be from the true population mean b) Using the Z-Test for the Mean, assume that the Null Hypothesis is trying to determine if the sample mean is statistically different from Population mean of 62.05 at an 95% Confidence Level. Fill out the below Alpha Value Z-Statistic 0.05 -1.959963985 Remember to Apply the Formula c) Set up the Two Tailed Test, describe what the testing is meant to show and complete the below: Z-Critical Value Lower Bound of Confidence Interval Upper Bound of Confidence Interval P-Value 1.6449 0.6788 This method uses the Alpha Value to create CI Interval This method uses the Z-Statistic Above to detemine P-Value. Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right. d) Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null Hypothesis e) Set up the Right Taled Test, describe what the testing is meant to show and complete the below: Z-Critical Value Lower Bound of Confidence Interval 1.6449 This method uses the Alpha Value to create Ci Interval This method uses the Z-Statistic Above to detemine P-Value. Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right. Upper Bound of Confidence Interval P-Value Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null Hypothesis

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Can You answer part D, E and F of this part!

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e)
Set up the Right Tailed Test, describe what the testing is meant to show and complete the
below:
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Z-Critical Value
Lower Bound of Confidence Interval
This method uses the Alpha Value to create CI IntervalsE
This method uses the Z-Statistic Above to determine P-Value.
Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right.
1.6449
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Upper Bound of Confidence Interval
P-Value
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Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null
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Нуpothesis
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If we lower the Confidence Level from 95% to 90%, what impact does it have on your
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conclusion on the Two Tailed and Right Tailed Test? Show all work.
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Explain
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Transcribed Image Text:Home Insert Page Layout Formulas Data Review View Cut Arial 10 A A- Wrap Text General Copy - Paste +.0 .00 00 +.0 Conditional Format Formatting as Table Merge & Center Ce Sty Format J8 X v fx A B. C. D. H. K 37 38 39 63 63 63 63 63 40 e) Set up the Right Tailed Test, describe what the testing is meant to show and complete the below: 41 42 63 43 63 Z-Critical Value Lower Bound of Confidence Interval This method uses the Alpha Value to create CI IntervalsE This method uses the Z-Statistic Above to determine P-Value. Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right. 1.6449 44 63 45 46 64 64 Upper Bound of Confidence Interval P-Value 64 64 47 48 Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null 49 64 64 Нуpothesis 50 51 64 52 64 53 64 54 64 9) If we lower the Confidence Level from 95% to 90%, what impact does it have on your 55 65 conclusion on the Two Tailed and Right Tailed Test? Show all work. 56 57 65 65 Explain 58 65 59 65 65 60 61 65 62 65 63 65 64 65 65 65 66 65 67 66 68 66 69 67 70 67 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 || |皿
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View
A Cut
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A A-
Copy
E Wrap Text
General
Paste
關!
指
Format
Merge & Center
+.0
.00
Conditional Format
Cell
Styles
Insert
Formatting as Table
J8
A x v fx
A
B
F.
H.
1.
Height
K
M.
Assume that the distribution of heights of young women aged 16 to 22 is approximately Normal
with mean u = 62.05 inches. A random sample of 73 female undergraduate students at a
University produced a sample mean height of can be derived from the adjacent chart.
2.
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6.
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SHOW YOUR FORMULAS AND ALL WORK ON THIS PAGE
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8.
a)
Using the data set, perform an analysis to determine the below. Assume the Standard
9.
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Deviation for the Sample is the same as the Standard Deviation of the Population:
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Mean
Standard Deviation
Standard Error
62.65753425
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2.95906882
0.346332809
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Explain the difference between the Stardard Deviation and Standard Error
The standard deviation measurethe amount of dispersion from the individual data while the standard errar of the mean measure how the mean of the data is likely to be from the true population mean.
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b)
sample mean is statisticaly different from Population mean of 62.05 at an 95% Confidence
Level. Fill out the below
Using the Z-Test for the Mean, assume that the Null Hypothesis is trying to determine if the
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Alpha Value
Z-Statistic
0.05
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-1.959963985
Remember to Apply the Formula
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c)
below:
Set up the Two Tailed Test, describe what the testing is meant to show and complete the
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Z-Critical Value
1.6449
This method uses the Alpha Value to create CI Interval
This method uses the Z-Statistic Above to determine P-Value.
Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right.
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Lower Bound of Confidence Interval
Upper Bound of Confidence Interval
0.6788
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P-Value
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d)
Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null
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Hypothesis
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e)
Set up the Right Tailed Test, describe what the testing is meant to show and complete the
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below:
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Z-Critical Value
1.6449
Lower Bound of Confidence Interval
Upper Bound of Confidence Interval
P-Value
This method uses the Alpha Value to create CI Interval
This method uses the Z-Statistic Above to determine P-Value.
Hint: Remember, if the Z-Statistic is posilive that the Chart reads left to right.
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Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null
Hypothesis
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Confidence Level
Hypothesis Testing
Transcribed Image Text:Home Insert Page Layout Formulas Data Review View A Cut Arial 10 A A- Copy E Wrap Text General Paste 關! 指 Format Merge & Center +.0 .00 Conditional Format Cell Styles Insert Formatting as Table J8 A x v fx A B F. H. 1. Height K M. Assume that the distribution of heights of young women aged 16 to 22 is approximately Normal with mean u = 62.05 inches. A random sample of 73 female undergraduate students at a University produced a sample mean height of can be derived from the adjacent chart. 2. 56 56 4 56 57 6. 58 SHOW YOUR FORMULAS AND ALL WORK ON THIS PAGE 58 58 8. a) Using the data set, perform an analysis to determine the below. Assume the Standard 9. 58 58 Deviation for the Sample is the same as the Standard Deviation of the Population: 10 11 59 Mean Standard Deviation Standard Error 62.65753425 12 59 2.95906882 0.346332809 13 60 14 15 16 17 60 60 61 61 Explain the difference between the Stardard Deviation and Standard Error The standard deviation measurethe amount of dispersion from the individual data while the standard errar of the mean measure how the mean of the data is likely to be from the true population mean. 18 61 19 61 b) sample mean is statisticaly different from Population mean of 62.05 at an 95% Confidence Level. Fill out the below Using the Z-Test for the Mean, assume that the Null Hypothesis is trying to determine if the 20 61 21 22 23 61 62 62 Alpha Value Z-Statistic 0.05 24 62 -1.959963985 Remember to Apply the Formula 25 62 26 62 c) below: Set up the Two Tailed Test, describe what the testing is meant to show and complete the 27 62 62 28 29 62 Z-Critical Value 1.6449 This method uses the Alpha Value to create CI Interval This method uses the Z-Statistic Above to determine P-Value. Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right. 30 62 Lower Bound of Confidence Interval Upper Bound of Confidence Interval 0.6788 31 62 32 62 P-Value 33 34 35 62 62 d) Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null 62 Hypothesis 36 63 37 63 63 63 38 39 40 63 e) Set up the Right Tailed Test, describe what the testing is meant to show and complete the 41 63 below: 42 63 43 63 Z-Critical Value 1.6449 Lower Bound of Confidence Interval Upper Bound of Confidence Interval P-Value This method uses the Alpha Value to create CI Interval This method uses the Z-Statistic Above to determine P-Value. Hint: Remember, if the Z-Statistic is posilive that the Chart reads left to right. 44 63 64 64 45 46 47 84 48 64 64 64 Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null Hypothesis 49 50 51 64 52 64 Confidence Level Hypothesis Testing
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