Assume that the normally distributed variable X having mean 17 and standard deviation 2.5, find (a) P(X < 13), (b) the value of m such that P(X m)= 0.2912; (d) P(14

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Chapter1: Combinatorial Analysis
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Plz solve only b) and c)
Assume that the normally distributed variable X having mean 17 and standard deviation 2.5, find
(a) P(X < 13);
(b) the value of m such that P(X <m)%= 0.2206;
(c) the value of m such that P(X >m)=0.2912,
(d) P(14<X< 19).
Click here to view page 1 of the standard normal distribution table
Click here to view page 2 of the standard normal distribution table
(a) P(X< 13) =|
(Round to four decimal places as needed.)
(b) m =
(Round to two decimal places as needed.)
(c) m =
(Round to two decimal places as needed.)
(d) P(14 <X< 19)=D
(Round to four decimal places as needed.)
Transcribed Image Text:Assume that the normally distributed variable X having mean 17 and standard deviation 2.5, find (a) P(X < 13); (b) the value of m such that P(X <m)%= 0.2206; (c) the value of m such that P(X >m)=0.2912, (d) P(14<X< 19). Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table (a) P(X< 13) =| (Round to four decimal places as needed.) (b) m = (Round to two decimal places as needed.) (c) m = (Round to two decimal places as needed.) (d) P(14 <X< 19)=D (Round to four decimal places as needed.)
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