Assume the following method is outside the class of KWArrayList class but has access to the methods of KWArrayList class public static void Unknown(KWArrayList list1, KWarrayList list2) If (ist1.size() == 0 || list2.size() ==0) return; int loop; if (list1.size() < list2.size()) loop= list1.size(); else loop= list2.size(); for (int i=0; i
Assume the following method is outside the class of KWArrayList class but has access to the methods of KWArrayList class public static void Unknown(KWArrayList list1, KWarrayList list2) If (ist1.size() == 0 || list2.size() ==0) return; int loop; if (list1.size() < list2.size()) loop= list1.size(); else loop= list2.size(); for (int i=0; i
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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* Question Completion Status:
Assume the following method is outside the class of KWArrayList class but has access to the methods
of KWArrayList class
public static void Unknown(KWArrayList<Integer> list1, KWarrayList<Integer> list2)
{
if (list1.size() == 0 || list2.size() ==0) return;
int loop;
if (list1.size() < list2.size())
loop= list1.size();
else loop= list2.size();
for (int i=0; i<loop; i++)
list1.set(i,(Integer) list1.get(i) + (Integer) list2.get(i))
}
O a. It changes the elements of list1 as each element in list1 would be the summation of the old value in list1 with
the corresponding value in list 2 based on the size of the larger list, list1 or list2.
O b. It changes the elements of list1 as each element in list1 would be the summation of the old value in list1 with
the corresponding value in list 2 based on list1 size.
O c. It changes the elements of list1 as each element in list1 would be the summation of the old value in list1 with
the corresponding value in list 2 based on list2 size.
O d. It changes the elements of list1 as each element in list1 would be the summation of the old value in list1 with
the corresponding value in list 2 based on the size of the smaller list, list1 or list2.
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