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- Given the IntNode class, define the findMax() method in the CustomLinkedList class that returns the largest value in the list or returns -99 if the list is empty. Assume all values in the list are non-negative. Ex: If the list contains: head -> 14 -> 191 -> 186 -> 181 findMax(headObj) returns 191. Ex: If the list contains: head -> findMax(headObj) returns -99. public class CustomLinkedList { public static int findMax(IntNode headObj) { if (headObj.getNext() == null) { return -99; // List is empty } int max = headObj.getNext().getData(); IntNode current = headObj.getNext().getNext(); // Traverse the linked list to find the maximum value while (current != null) { int data = current.getData(); if (data > max) { max = data; } current = current.getNext(); } return max; } public static void main(String[] args) { IntNode headObj;…If myList is a declared ADT list and the front of the list is on the left, what does the method getEntry(3) return after applying the following pseudo code? myList.add("horse")myList.add("goat")myList.add(1, "fish")myList.add("cat")myList.add(2, "dog")myList.remove(4)goatdoghorsecatWrite a method to insert an item in a sorted list where the items are kept in a linked list named (first address of the list) "greenlist" and the method has the signature: void InsertItem(ItemType green)only the method using C++
- Assume that the following method is within the KWLinkedList class, what does this method do? public boolean undefined(E item) { if(head == null) return false; Node<E> p = head.next; Node<E> newNode= new Node<E>(item, p); newNode.prev = head; head.next = newNode; p.prev = newNode; size++; return true; } nserts a new node with its data as item at the front of the list. Inserts a new node with its data as item after the first node of the list. Deletes the node with its data as item. Inserts a new node with its data as item, at the end of the list.Write the following method that partitions the list using thefirst element, called a pivot:public static int partition(int[] list)After the partition, the elements in the list are rearranged so all the elements beforethe pivot are less than or equal to the pivot, and the elements after the pivot aregreater than the pivot. The method returns the index where the pivot is located inthe new list. For example, suppose the list is {5, 2, 9, 3, 6, 8}. After the partition,the list becomes {3, 2, 5, 9, 6, 8}. Implement the method in a way that takes atmost list.length comparisons. See liveexample.pearsoncmg.com/dsanimation/QuickSortNeweBook.html for an animation of the implementation. Write atest program that prompts the user to enter the size of the list and the contents ofthe list and displays the list after the partition. Here is a sample run. Enter list size: 8 ↵EnterEnter list content: 10 1 5 16 61 9 11 1 ↵EnterAfter the partition, the list is 9 1 5 1 10 61 11 16Given that values is of type LLNode<Integer> and references a linked list (possibly empty) of Integer objects, what does the following code do if invoked as mystery(values)? int mystery(LLNode<Integer> list) { if (list == null) return 0; else return list.getInfo() + mystery(list.getLink()); } A.returns how many numbers are on the values list. B. returns sum of the numbers on the values list. C. returns 0 D. returns the last number on the values list
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- Sometimes a number is the same when you read it from front to back and from back to front. Two easy examples are 123321 and 891232198. Write a Method Called makePalindrome() that will return a linked list with a palindrome of the calling list. Example [1,2,3] must return [1,2,3,3,2,1] and [8,9,1,4] must return [8,9,1,4,4,1,9,8]. In Java write a test programAssume that the following method is added to the class KWLinkedList. What does this method do? public boolean question() { if (size%2 == 1 || size < 2) return false; Node<E> h = head; for(int i = 0; i < size/2; i++) h=h.next; Node<E> p = head; while (h!= null) { if (! p.data.equals(h.data)) return false; p = p.next; h = h.next; } return true; } Compare the elements of the first half of the list with the second half, if any one node has the same data value, it will return false, else it will return true. Compare the elements of the first half of the list with the second half, if all the nodes have the same data values, it will return true else, it will return false. Compare the elements of the first half of the list with the second half, if all the nodes have the same data values, it will return false else, it will return true…Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts public class ItemNode { private String item; private ItemNode nextNodeRef; // Reference to the next node public ItemNode() { item = ""; nextNodeRef = null; } // Constructor public ItemNode(String itemInit) { this.item = itemInit; this.nextNodeRef = null; } // Constructor public ItemNode(String itemInit, ItemNode nextLoc) {…