Assume there're n film categories. Let L = Min(L1, L2, .. Ln) where Li = the length of the longest film in the ith category. Please write a single SQL query that finds all films whose lengths are greater than L
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Assume there're n film categories. Let L = Min(L1, L2, .. Ln) where Li = the length of the longest film in the ith category.
Please write a single SQL query that finds all films whose lengths are greater than L.
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- Write, but do not execute, the commands to grant the following privileges: a. User Ashton must be able to retrieve data from the ITEM table. b. Users Kelly and Morgan must be able to add new orders and order lines. c. User James must be able to change the price for all items. d. User Danielson must be able to delete customers. e. All users must be able to retrieve each customers number, name, street, city, state,and postal code. f. f User Pere7 must be able to create an index on the ORDFRS table. g. User Washington must be able to change the structure of the ITEM table. h. User Grinstead must have all privileges on the ORDERS table.A new table has been requested to support tracking automated emails sent to customers. Create the table and add data as described below. Tablename: email_log Columns: emailid (numeric), emaildate (datetime), customer# (numeric) Primary key: emailid column, define as an Identity Column Add the following data rows and display resulting rows (if any errors occur, explain why the error is expected) Emaildate = current date, customer# = 1007 Emailid = specify to use the column default value, emaildate = current date, customer# = 1008 Emailid = 25, emaildate = current date, customer# = 1009As per our guidelines, we are supposed to answer only 1st three parts. Kindly repost the remaining questions separately. 4.1 use gym_29876543 4.2 db.createCollection("userProfiles") db.userProfiles.insertMany([ {"Name" : "Dominic","Surname":"Badeaux","Date_of_Birth":1982-09-04,"FitnessLevel":1}, {"Name" : "John","Surname":"Dlamini","Date_of_Birth":1974-05-18,"FitnessLevel":2} ]) 4.3 db.userProfiles.find() arrow_forward Step 2 Complete code: use gym_29876543 db.createCollection("userProfiles") db.userProfiles.insertMany([ {"Name" : "Dominic","Surname":"Badeaux","Date_of_Birth":1982-09-04,"FitnessLevel":1}, {"Name" : "John","Surname":"Dlamini","Date_of_Birth":1974-05-18,"FitnessLevel":2} ]) db.userProfiles.find() Q.4.4 Query all the user profiles where the fitness level of the user is equal to 2. Q.4.5 Query all the user profiles where the date of birth of the user is from 1980‐01‐01 to1982‐12‐31 (including both dates)
- 8. In the following code below, the code selects an Employee object by primary key. However you are missing the line of code to create the employee variable. What line of code are you missing? [HttpGet] public IActionResult Edit(int id) { ViewBag.Action = "Edit"; ViewBag.Departments = context.Departments.OrderBy(d => d.DepartmentName).ToList(); ________________________________________________ return View(employee); } 1. var employee = id 2. var employee ="select * from Employee where Id = id"; 3. var employee = context.Employees.Find(id); 4. context.Employees.Find(id) = employee;3.9 LAB - Select lesson schedule with inner join The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule. Hint: Perform a join on the Student and LessonSchedule tables, matching the student IDs.Can you explain why this code does not insert information into the database but displays an error with the text:->Please select a product type<br>Please enter a product name<br>Please enter a valid product price<br>Please enter a product SKU<br>Please enter a product attribute rest of the code as image <?php require_once '../src/db/Db.php'; //attempt to connect to the database try { $pdo = Db::getConnection(); $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); } catch (PDOException $e) { echo 'Error connecting to database: ' . $e->getMessage(); exit; } // Report all PHP errors error_reporting(E_ALL); // Display errors ini_set('display_errors', 1); ini_set('display_startup_errors', 1); if ($_SERVER['REQUEST_METHOD'] === 'POST') { // retrieve form data $type = $_POST['type'] ?? ''; $name = $_POST['name'] ?? ''; $price = $_POST['price'] ?? ''; $sku = $_POST['sku'] ?? ''; $attribute = $_POST['attribute'] ?? ''; //Perform validation $errors =…
- //2. createSelectOptions //a. Test users JSON data available here: https://jsonplaceholder.typicode.com/users//b. For testing (not in function) you may want to define users with the test data.//c. Receives users JSON data as a parameter//d. Returns undefined if no parameter received//e. Loops through the users data//f. Creates an option element for each user with document.createElement()//g. Assigns the user.id to the option.value//h. Assigns the user.name to the option.textContent//i. Return an array of options elements This is what I have so far passes a, c, d fails rest help please function createSelectOptions(users) { return users.map((x) => x.option); }Create table Medicine (MInventory_Id int primary key, M_Name varchar (40), Manufacturer varchar (40), Price varchar (20), Quantity int, Exp_Date date); Create table PrescriptionMedicine (Prescription_Id int primary key, MInventory_Id int); Example of a table (Medicine) Insert into Medicine values(101, ‘Biaxin’, ‘Pfizers’, ‘$10.99’, 1, 10/5/02); Insert into MedicineRead the data into a DataFrame with ID as the index. Convert the “Hired” column into Date/Time data type Create a new column with years of experience with the company at present without rounding. Create a new Boolean column for senior status with employees with at least 10 years of experience as senior and others are not. Create a new column for longevity pay equal to $150 per whole year of experience in the company. Create a list of column names for each data type in the DataFrtame.
- Add a connection string in the appsettings.json file.Open the Startup.cs file to add the SQL server db provider for EF Core. Add the code services.AddDbContext<ProductContext>(o => o.UseSqlServer(Configuration.GetConnectionString("ProductDB"))); under ConfigureServices method. Note that in the GetConnectionString method the name of the key of the connection string is passed that was added in appsettings file.The following schema is given (primary keys are bold): ARTWORK (ArtworkCode. Title, Author, BasicAuction Price, FinalSalePrice". NumParticipantingBuyers", FinalBuyerID") OFFER (ArtworkCode, BuyerID, Date, Amount) REQUEST AUCTION ENDING (ArtworkCode. Auction EndingDate, Description) Write the trigger to manage the following activities related to an online auction of artworks. The ARTWORK table contains the list of artworks sold at the auction. The OFFER table contains, for each artwork, a list of the amounts that have been offered by buyers interested in purchasing the artwork. The same buyer can make multiple offers for the same artwork on different dates. A request to end the auction for an artwork is generated (inserting a record into the table REQUEST AUCTION ENDING), If there was no offer for the artwork, the trigger ends with an error. Otherwise, you have to calculate the following information. (1) The final sale price of the artwork, corresponding to the highest amount offered…1- Display contact First name and contact Last name for customers after sorting the customersby their contact Last name in ascending order.2- selects the order line items (orderNumber, orderlinenumber) from the “orderdetails” table.Also, display the subtotal (quantityOrdered * priceEach) for each line item and sorts the resultset based on the subtotal descending .3- Display unique last names from employees table ordered by last name.4- Display customerNumber, customerName and creditLimit for getting the top five customerswho have the highest creditLimit.5- Find customer Name, customer country, sales representative employee number fromcustomers who do not have a sales representative.6- For each order status, display status and count of orders have this status.7- For Each order number in order details table, Display order number, sum of quantity ordered(itemsCount) and sum of (priceEach * quantityOrdered) as total. With condition “total”greater than 1000.8- Display product code, product…