Assuming the conditions are met, based on the t-statistic of 1.80 the appropriate conclusion for this test using α = .05 is: (Check the t-table) Choices in picture
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- We are doing an experiment to see if Psych majors do better on a test than Econ majors. The null hypothesis is that they do equally well on the test. We get the results, and Psych majors and Econ majors do equally well. What is our conclusion?A foreign car manufacturer advertises that its newest model, the Bullet, rarely stops at gas stations. In fact, they claimed that its EPA rating for highway driving is at least 32.5 mpg. However, the results of a recent independent study determined the mpg for 50 identical models of the Bullet, with these results: n = 50, x= 30.4 mpg, and s = 5.3 mpg.This report failed to offer any conclusion, and you have been asked to interpret these results by someone who has always felt that the 32.5 figure is too high. What would be your conclusion using a significance level of 5%?Z = 1.645A boss wants to show that productivity decreases when the boss leaves the office. An office of 26 employees handed in productivity reports when the boss was absent (M1=5, SS1=250) compared to 36 employees who handed in reports when the boss was present (M2=8, SS2=420). a) What is the null and alternative hypothesis? a Ho:μ 1-μ2≠0; H1:μ 1-μ2=0 b Ho:μ 1-μ2<0; H1:μ 1-μ2>0 c Ho:μ 1-μ2=0; H1:μ 1-μ2≠0 d Ho:μ 1-μ2>0; H1:μ 1-μ2<0 b) Compute tobt? c) Compute df? d) Given the α=0.05, compute the negative value of tcrit? e) Is tobt significant?
- I am most confused on how to know if you use less than or greater than for the alternative hypothesis??Could you please help me out with this question… Does ivy grow better in areas with more sun versus in shady areas? Formulate one null (H0) and one alternative (H1) hypothesis.A) The p− value is 0.7580. Reject the null hypothesis H0. The social media content associate has sufficient evidence that the average number of social media posts per day that helps to build an audience is different than 3 daily posts. B)The p− value is 0.2420. Reject the null hypothesis H0. The social media content associate has sufficient evidence that the average number of social media posts per day that helps to build an audience is different than 3 daily posts. C)The p− value is 0.7580. Fail to reject the null hypothesis H0. The social media content associate does NOT have sufficient evidence that the average number of social media posts per day that helps to build an audience is different than 3 daily posts. D)The p− value is 0.2420. Fail to reject the null hypothesis H0. The social media content associate does NOT have sufficient evidence that the average number of social media posts per day that helps to build an audience is different than 3 daily posts.
- A researcher selects a sample and administers a treatment for anxiety to the individuals in the sample. If the sample is used for a hypothesis test, what does the null hypothesis ( H 0) put forth about the treatment? a. The treatment multiplies each anxiety score by a constant. b. The treatment has an effect on anxiety. c. The treatment has no effect on anxiety. d. The treatment divides each anxiety score by a constant.A researcher wants to explore the differences in health effects from two different types of sugar. She hypothesizes that artificial sweetener has lower long term health benefits than natural sugar. What is her null hypothesis? Fill in the blank. H0: μArtificalSweetener__________ μNaturalSugar Group of answer choices a) Less than b) Less than or equal to c) Greater than d) Greater than or equal toA medical researcher wants to examine the relationship of the blood pressure of patients before and after a procedure. She takes a sample of people and measures their blood pressure before undergoing the procedure. Afterwards, she takes the same sample of people and measures their blood pressure again. The researcher wants to test if the blood pressure measurements after the procedure are different from the blood pressure measurements before the procedure. The hypotheses are as follows: Null Hypothesis: μD = 0, Alternative Hypothesis: μD ≠ 0. From her data, the researcher calculates a p-value of 0.5704. What is the appropriate conclusion? The difference was calculated as (after - before). Question 16 options: 1) The average difference in blood pressure is significantly different from 0. The blood pressures of patients differ significantly before and after the procedure. 2) We did not find enough evidence to say the average…
- A researcher hypothesizes that Drug A is more effective than Drug B. In conducting an analysis to test this hypothesis, how should the null hypothesis be stated? a. H0: μDrug A = μDrug B b. H0: μDrug A > μDrug B c. H0: μDrug A ≠ μDrug B d. H0: μDrug A < μDrug BAt a manufacturing company, the percent of defective items produced on the assembly line is 2%. The company is testing a new assembly line designed to reduce the percent of defective parts. The null and alternative hypotheses of the test are described as follows. H0:The percent of defective parts is at least 2%.Ha:The percent of defective parts is less than 2%. H0:The percent of defective parts is at least 2%.Ha:The percent of defective parts is less than 2%. Which of the following describes a Type IIII error that could result from the test?At a manufacturing company, the percent of defective items produced on the assembly line is 2%. The company is testing a new assembly line designed to reduce the percent of defective parts. The null and alternative hypotheses of the test are described as follows. H0:The percent of defective parts is at least 2%.Ha:The percent of defective parts is less than 2%.H0:The percent of defective parts is at least 2%.Ha:The percent of defective parts is less than 2%. Which of the following describes a Type IIII error that could result from the test? The test does not provide convincing evidence that the percent is less than 2%, but the actual percent is 3%. A The test does not provide convincing evidence that the percent is less than 2%, but the actual percent is 2%. B The test does not provide convincing evidence that the percent is less than 2%, but the actual percent is 1%. C The test provides convincing evidence that the percent is less than 2%, but the…