Question
Asked Nov 25, 2019
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Assuming the density of a 5% acetic acid by mass solution is 1.0 g/mL, determine the volume of the acetic acid solution necessary to neutralize 25.0 mL of 0.100 M NaOH. Also record this calculation. 
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Expert Answer

Step 1

Given,

Density = 5%,

Mass = 1.0 g/ ml

NaOH is 25 ml of 0.1 M

5 ...

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Molarity of the acetic acid solution is calculated as follows Molar mass of acetic acid 60.052 g/mol The balanced equation is given below CH,COOH NaOH >CH,COONa H20 The number of moles is calculated as follows, Weight of the substance The number of moles Molar mass of the substance 5 g Number of moles 60.052 g/mole Number of moles = 0.0833

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