Question
Asked Nov 13, 2019
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Assuming the Earth's magnetic field averages about 0.50×10−4 T near Earth's surface, estimate the total energy stored in this field in the first 6.0 km above Earth's surface. The radius of Earth is 6380 km?

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Expert Answer

Step 1

Consider the magnetic field of Earth is denoted by B, Earth’s radius is denoted by R and R’ is the distance above the surface of the earth.

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B 0.5x 10 T R 6380 km R' 6 km

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Step 2

Write the formula for energy density (UB) of the magnetic field and plug required values to find it.

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В? U В 2Ho (0.5x10 T) (4л х107 H/m) -9.952 x10 J/m3

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Step 3

Find the effective volume (Vef...

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r(R+ R' R V eff 3 3 [(R+R-R 3 4 3 (6830 km +6 km)-(6380 km) 3 3 10 m 2.5x 10 km3 1km =2.5 x 1020 m3

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