At 248°C and 1 bar pressure, antimony (V) chloride is 71.8% dissociated according to the reaction: SbCls (g) = SbCl; (g) + C2 (g). The equilibrium constant for the reaction under these conditions was calculated to be 1.064. If nitrogen gas is present in the equilibrium mixture and has a partial pressure of 0.40 bar, what is degree of dissociation of SbCls under the same conditions of temperature and total pressure? [Answer: 80.0%]

At 248°C and 1 bar pressure, antimony (V) chloride is 71.8% dissociated according to the reaction: SbCls (g) = SbCl; (g) + C2 (g). The equilibrium constant for the reaction under these conditions was calculated to be 1.064. If nitrogen gas is present in the equilibrium mixture and has a partial pressure of 0.40 bar, what is degree of dissociation of SbCls under the same conditions of temperature and total pressure? [Answer: 80.0%]

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 14.3QE: Describe a nonchemical system that is not in equilibrium, and explain why equilibrium has not been...

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