At 35°C, K = 1.5 x 10 ^-5 for the reaction2 NOCl(g)-->2 NO (g) + Cl2 (g)Calculate the concentrations of all species at equilibrium for each of the following original mixtures. 2.2 moles of pure NOCl in a 2.0-L flask[NOCl] = M?[NO] = M?[Cl2 ] = M?1.0 mole of NOCl and 1.0 mole of NO in a 1.0-L flask[NOCl] = M?[NO] = M?[Cl2 ] = M?3.0 mole of NOCl and 1.0 mole of Cl2 in a 1.0-L flask[NOCl] = M?[NO] = M?[Cl2 ] = M?

Equilibrium constant is given as K = Equilibrium concentration of products/ Equilibrium…

Answered: At 35°C, K = 1.5 x 10 ^-5 for the…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 34QRT

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At 35°C, K = 1.5 x 10 ^-5 for the reaction

2 NOCl(g)-->2 NO (g) + Cl₂(g)

Calculate the concentrations of all species at equilibrium for each of the following original mixtures.

2.2 moles of pure NOCl in a 2.0-L flask

[NOCl] = M?

[NO] = M?

[Cl₂ ] = M?
1.0 mole of NOCl and 1.0 mole of NO in a 1.0-L flask

[NOCl] = M?

[NO] = M?

[Cl₂ ] = M?
3.0 mole of NOCl and 1.0 mole of Cl₂ in a 1.0-L flask

[NOCl] = M?

[NO] = M?

[Cl₂ ] = M?

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