At 35°C, K = 2.0 x 10-5 for the reaction 2 NOCI(g) = 2 NO(g) + Cl2 (g) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 2.6 moles of pure NOCI in a 2.0-L flask [NOCI] M NO] = [Cl2] M = b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask [NOCI] [NO] = M [Cl2] = M c. 3.2 mole of NOCI and 1.0 mole of Cl2 in a 1.0-L flask [NOCI] M [NO] M [Cl2] =

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Chapter12: Chemical Equilibrium
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Problem 12.22PAE
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At 35°C,
K =
2.0 x 10-5 for the reaction
2 NOCI(g) = 2 NO(g)+ Cl2 (g)
Calculate the concentrations of all species at equilibrium for each of the following original mixtures.
a. 2.6 moles of pure NOCl in a 2.0-L flask
[NOCI]
M
[NO]
M
%3D
[Cl2] =
M
b. 1.0 mole of
NOC1 and 1.0 mole of
NO in a 1.0-L flask
[NOCI] =
M
[NO] :
M
[Cl) ]
M
%3D
С. 3.2 mole of
NOCI and 1.0 mole of
Cl2 in a 1.0-L flask
[NOCI]
M
[NO]
M
%D
[Cl2]
M
Transcribed Image Text:At 35°C, K = 2.0 x 10-5 for the reaction 2 NOCI(g) = 2 NO(g)+ Cl2 (g) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 2.6 moles of pure NOCl in a 2.0-L flask [NOCI] M [NO] M %3D [Cl2] = M b. 1.0 mole of NOC1 and 1.0 mole of NO in a 1.0-L flask [NOCI] = M [NO] : M [Cl) ] M %3D С. 3.2 mole of NOCI and 1.0 mole of Cl2 in a 1.0-L flask [NOCI] M [NO] M %D [Cl2] M
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