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At –90°C, K for the reaction           N2O4(g)  ↔  2NO2(g) is 4.66 × 10–8. We introduce 0.038 mol of N2O4 into a 2.3-L vessel at –90°C and let equilibrium be established. The total pressure in the system at equilibrium will be   Question 23 options:   A)  4.66 × 10–8 atm.   B)  0.25 atm.   C)  0.12 atm.   D)  0.50 atm.   E)  0.23 atm.

At –90°C, K for the reaction           N2O4(g)  ↔  2NO2(g) is 4.66 × 10–8. We introduce 0.038 mol of N2O4 into a 2.3-L vessel at –90°C and let equilibrium be established. The total pressure in the system at equilibrium will be   Question 23 options:   A)  4.66 × 10–8 atm.   B)  0.25 atm.   C)  0.12 atm.   D)  0.50 atm.   E)  0.23 atm.

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 41QRT: Nitrosyl chloride, NOC1, decomposes to NO and Cl2 at high temperatures. 2 NOCl(g) ⇌ 2 NO(g) +...
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At –90°C, K for the reaction

          N2O4(g)  ↔  2NO2(g)

is 4.66 × 10–8. We introduce 0.038 mol of N2O4 into a 2.3-L vessel at –90°C and let equilibrium be established. The total pressure in the system at equilibrium will be

 

Question 23 options:

 

A) 

4.66 × 10–8 atm.
 

B) 

0.25 atm.
 

C) 

0.12 atm.
 

D) 

0.50 atm.
 

E) 

0.23 atm.

 
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