At t=0, a ball is thrown with an initial velocity of magnitude 15ms-1 at 75° to the horizontal (upwards). Which way is the ball moving at this time? What is the magnitude of the horizontal component of velocity at t=2.0s?

At t=0, a ball is thrown with an initial velocity of magnitude 15ms-1 at 75° to the horizontal (upwards). Which way is the ball moving at this time? What is the magnitude of the horizontal component of velocity at t=2.0s?

Name: At t=0, a ball is thrown with an initial velocity of magnitude 15ms-1
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: At t=0, a ball is thrown with an initial velocity of magnitude 15ms-1 at 75° to the horizontal (upwards). Which way is the ball moving at this time?What is the magnitude of the horizontal component of velocity at t=2.0s?

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 8CQ: Answer the following questions for projectile motion on level ground assuming negligible air...

See similar textbooks

Similar questions

Answer the following questions for projectile motion on level ground assuming negligible air resistance, with the initial angle being neither 0 nor 90 : (a) Is the acceleration ever zero? (b) Is the vector v ever parallel or antiparallel to the vector a? (c) Is the vector v ever perpendicular to the vector a? If so, where is this located?
A pilot flies horizontally at 1300 km/h, at height h = 35 m above initially level ground. However, at time t = 0, the pilot begins to fly over ground sloping upward at angle u = 4.3°. If the pilot does not change the airplane’s heading, at what time t does the plane strike the ground?
A skater is gliding along the ice at 2.2 m/s, when she undergoes an acceleration of magnitude 1.2 m/s2 for 3.0 s. At the end of that time she is moving at 5.8 m/s. (a) What must be the angle between the acceleration vector and the initial velocity vector?
In the figure, a ball is launched with a velocity of magnitude 7.00 m/s, at an angle of 41.0° to the horizontal. The launch point is at the base of a ramp of horizontal length d1 = 6.00 m and height d2 = 3.60 m. A plateau is located at the top of the ramp. Does the ball land on the ramp or the plateau? When it lands, what are the magnitude and angle of its displacement from the launch point?
In the figure, a ball is launched with a velocity of magnitude 6.00 m/s, at an angle of 44.0° to the horizontal. The launch point is at the base of a ramp of horizontal length d1 = 6.00 m and height d2 = 3.60 m. A plateau is located at the top of the ramp. (a) Does the ball land on the ramp or the plateau? When it lands, what are the (b) magnitude and (c) angle of its displacement from the launch point?
a ball is launched with a velocity of magnitude 10.0 m/s, at an angle of 50.0° to the horizontal.The launch point is at the base of a ramp of horizontal length d1 6.00 m and height d2 = 3.60 m. A plateau is located at the top of the ramp. (a) Does the ball land on the ramp or the plateau? When it lands, what are the (b) magnitude and (c) angle of its displacement from the launch point?
For a projectile fired at an angle of 48 degrees and having an initial velocity of 65 m/s, what is the horizontal component of the initial velocity?
As a projectile moves in its parabolic path, where are the velocity and acceleration vectors perpendicular to each other? (a) Everywhere along the projectile’s path, (b) at the peak of its path, (c) nowhere along its path, or (d) not enough information is given.
A ball is launched from ground level at 63 m/s at an angle of 54 degrees above the horizontal. How far does it go before it is at ground level again?
A cannon launches a cannonball from level ground with an initial speed of 80 m/s at an angle of 280 above the horizontal. What horizontal distance does the cannonball travel when the cannonball returns to the ground? Given the same initial velocity of launch, at what other angle above the ground can the cannonball be fired and achieve the same horizontal range as before? (Assume that g = 9.81 m/s2.) a. Range = 540 m, and angle = 420 above the horizontal b. Range = 600 m, and angle = 620 above the horizontal c. Range = 270 m, and angle = 620 above the horizontal d. Range = 540 m, and angle = 620 above the horizontal e. Range = 270 m, angle = 420 above the horizontal
If the vector components of the position of a particle moving in the xy plane as a function of time are x = (2.8 m/s2)t2 and y = (6.4 m/s3)t3, at what time t is the angle between the particle's velocity and the x axis equal to 45°?
A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 3.30 s, it is at point (4.40 m, 5.90 m) with velocity (2.70 m/s)ĵ and acceleration in the positive x direction. At time t2 = 12.0 s, it has velocity (–2.70 m/s)î and acceleration in the positive y direction. What are the (a) x and (b) y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.