A projectile is launched with a launch angle of 30° with respect to the horizontal direction and with an initial speed of 26 m/s. How do the vertical and horizontal components of the projectile's velocity vary with time?The initial velocity in the x-direction vx0 is related to the initial speed byvx0 = v0 cos 30°.The constant velocity in the x-direction means that the equation describing the time dependence of x for the particle, with x0 taken as 0, isx = x0 + vx0t = 0 + m/s t.The equation for the vertical coordinate, which is constantly accelerating downward at g = 9.8 m/s2, isy = y0 + vy0t − 12gt2 = m/s t+ m/s2 t2.

Name: A projectile is launched with a launch angle of 30° with respect to th
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: A projectile is launched with a launch angle of 30° with respect to the horizontal direction and with an initial speed of 26 m/s. How do the vertical and horizontal components of the projectile's velocity vary with time?The initial velocity in the x

The variation of vertical component with time is,

Answered: A projectile is launched with a launch…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 7OQ: A projectile is launched on the Earth with a certain initial velocity and moves without air...

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

A projectile is launched with a launch angle of 30° with respect to the horizontal direction and with an initial speed of 26 m/s.

How do the vertical and horizontal components of the projectile's velocity vary with time?

The initial velocity in the x-direction v_x0 is related to the initial speed by

v_x0 = v₀ cos 30°.

The constant velocity in the x-direction means that the equation describing the time dependence of x for the particle, with x₀ taken as 0, is

x = x₀ + v_x0t = 0 +

m/s

The equation for the vertical coordinate, which is constantly accelerating downward at g = 9.8 m/s², is

y = y₀ + v_y0t −

gt² =

m/s

m/s²

t².

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions