At the beginning of an advertising campaign for a new product in a city of 500,000 people, no one is aware of the product. After 10 days, 100,000 people are aware of the product. If N = N(t) is the number of people (in thousands) who are aware of the product t days after the beginning of the advertising campaign, solve the following differential equation for dN N(f): k(500 – N); N(0) = 0; N(10) = 100. %3D %3D %3D dt
At the beginning of an advertising campaign for a new product in a city of 500,000 people, no one is aware of the product. After 10 days, 100,000 people are aware of the product. If N = N(t) is the number of people (in thousands) who are aware of the product t days after the beginning of the advertising campaign, solve the following differential equation for dN N(f): k(500 – N); N(0) = 0; N(10) = 100. %3D %3D %3D dt
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:At the beginning of an advertising campaign for a new product in a city
of 500,000 people, no one is aware of the product. After 10 days, 100,000
people are aware of the product. If N = N(t) is the number of people (in
thousands) who are aware of the product t days after the beginning of
the advertising campaign, solve the following differential equation for
dN
N(t):
dt
k(500 – N); N(0) = 0; N(10) = 100.
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