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At the center of a 40.1 m diameter circular (frictionless) ice rink, a 72.8 kg skater travelling north at 1.14 m/s collides with and holds onto a 61.2 kg skater who had been heading west at 4.74 m/s. How long will it take them to glide to the edge of the rink? Ans: 8.90 s b)  Where will they reach it? Give your answer as an angle north of west. (Attached below is what I attempted for b), but apparently it is wrong)

At the center of a 40.1 m diameter circular (frictionless) ice rink, a 72.8 kg skater travelling north at 1.14 m/s collides with and holds onto a 61.2 kg skater who had been heading west at 4.74 m/s. How long will it take them to glide to the edge of the rink? Ans: 8.90 s b)  Where will they reach it? Give your answer as an angle north of west. (Attached below is what I attempted for b), but apparently it is wrong)

Horizons: Exploring the Universe (MindTap Course List)
Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN:9781305960961
Author:Michael A. Seeds, Dana Backman
Publisher:Michael A. Seeds, Dana Backman
Chapter6: Atoms And Spectra
Section: Chapter Questions
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(7a) At the center of a 40.1 m diameter circular (frictionless) ice rink, a 72.8 kg skater travelling north at 1.14 m/s collides with and holds onto a 61.2 kg skater who had been heading west at 4.74 m/s. How long will it take them to glide to the edge of the rink? Ans: 8.90 s

b)  Where will they reach it? Give your answer as an angle north of west. (Attached below is what I attempted for b), but apparently it is wrong)

4:16 PM Tue Oct 31 QPHYSICS 1A03 Notebook 5 < Cost: V vor vcaso using T 2.16m15 Î tano In west b) tano = 0.619 -2.16 direction In north direction -0.2865 0 16.0⁰ : Home Insert Draw ! Patter P before collision = before collision m₂v₂i = (m₂ + m₂) v coso 2 (61.2) (4.74): 134 1080 vioso: -2.16 mls after collision View vsing= P after collision m₂ V₂i = (m₁+m₂) using : (72.8) (1.14) : (72.8 +61.2) SING V sine = 82.992 134 0.619m 15 + Uf = √ (2.16)² + (0.619) ² vi: Vf: 2.25 m²s +- X÷ 4x= vit +! 20.05 2.25t t = 8.91 S 8 0 स्वहर 69% K 71
Transcribed Image Text:4:16 PM Tue Oct 31 QPHYSICS 1A03 Notebook 5 < Cost: V vor vcaso using T 2.16m15 Î tano In west b) tano = 0.619 -2.16 direction In north direction -0.2865 0 16.0⁰ : Home Insert Draw ! Patter P before collision = before collision m₂v₂i = (m₂ + m₂) v coso 2 (61.2) (4.74): 134 1080 vioso: -2.16 mls after collision View vsing= P after collision m₂ V₂i = (m₁+m₂) using : (72.8) (1.14) : (72.8 +61.2) SING V sine = 82.992 134 0.619m 15 + Uf = √ (2.16)² + (0.619) ² vi: Vf: 2.25 m²s +- X÷ 4x= vit +! 20.05 2.25t t = 8.91 S 8 0 स्वहर 69% K 71
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