At time t = 0, an electron with kinetic energy 9.2 keV moves through x O in the positive direction of an x axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 69.9 uT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinate x 18 cm? (a) Number i Units (b) Number Units

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter11: Magnetic Forces And Fields
Section: Chapter Questions
Problem 63AP: An electron of kinetic energy 2000 eV passes between parallel plates that are 1.0 an apart and kept...
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At time t = 0, an electron with kinetic energy 9.2 keV moves through x = 0 in the positive direction of an x axis that is parallel to the
%3D
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horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 69.9 uT. (a) What is
the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's
distance from the x axis in centimeters when the electron reaches coordinatex = 18 cm?
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(a) Number
i
Units
(b) Number
i
Units
>
Transcribed Image Text:At time t = 0, an electron with kinetic energy 9.2 keV moves through x = 0 in the positive direction of an x axis that is parallel to the %3D %3D horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 69.9 uT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinatex = 18 cm? %3D (a) Number i Units (b) Number i Units >
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