At what speed would a proton need to circle the Earth at a height of 1000 km above the equator if the Earth's magnetic field is horizontal and directed north-south, with an intensity of 4.00x 10-8 T? (The radius of the Earth is 6400 km and the charge and mass of the proton are q = 1.60x 10-19 c and mp = 1.67x 10-27 kg. Ignore relativistic corrections.)

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter22: Magnetic Forces And Magnetic Fields
Section: Chapter Questions
Problem 1P: A proton travels with a speed of 3.00 106 m/s at an angle of 37.0 with the direction of a magnetic...
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At what speed would a proton need to circle the Earth at a height of 1000 km above the equator if the Earth's magnetic field is
horizontal and directed north-south, with an intensity of 4.00x 10-8 T? (The radius of the Earth is 6400 km and the charge and mass
of the proton are q = 1.60x 10-19 c and mp = 1.67x 10-27 kg. Ignore relativistic corrections.)
Transcribed Image Text:At what speed would a proton need to circle the Earth at a height of 1000 km above the equator if the Earth's magnetic field is horizontal and directed north-south, with an intensity of 4.00x 10-8 T? (The radius of the Earth is 6400 km and the charge and mass of the proton are q = 1.60x 10-19 c and mp = 1.67x 10-27 kg. Ignore relativistic corrections.)
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