At 2040 oC the equilibrium constant for the reaction: 2 IBr(g)  I2(g) + Br2(g) is KP = 0.649. If the initial pressure of IBr is 0.00138 atm, what are the equilibrium partial pressures of IBr, I2, and Br2? p(IBr) =   . p(I2) =   . p(Br2) =   .

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