At 288 oC the equilibrium constant for the reaction: 2 HI(g)(equilibrium arrows) H2(g) + I2(g) is KP = 2.51e-10. If the initial pressure of HI is 0.00240 atm, what are the equilibrium partial pressures of HI, H2, and I2?

At 288 oC the equilibrium constant for the reaction: 2 HI(g)(equilibrium arrows) H2(g) + I2(g) is KP = 2.51e-10. If the initial pressure of HI is 0.00240 atm, what are the equilibrium partial pressures of HI, H2, and I2?

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 30P

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Question

At 288 ^oC the equilibrium constant for the reaction:

2 HI(g)(equilibrium arrows) H₂(g) + I₂(g)

is K_P = 2.51e-10. If the initial pressure of HI is 0.00240 atm, what are the equilibrium partial pressures of HI, H₂, and I₂?

p(HI) =  .

p(H₂) =  .

p(I₂) =  .

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