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- Prove cosh 2 x - sinh 2 x =1At time 0, M is deposited into Fund X, which accumulates at a force of interest δt = 0.006t2(0.006 t square). At time m, 2M is deposited into Fund Y, which accumulates at an annual effective rate of 10%. At time n, where ? > ?, the accumulated value of each fund is 4M. Determine m.Use the intermediate value theorem to show that there is a solution to x− √ x−ln x = 0 on the interval (2, 3). Clearly explain your reasoning.