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B (a) A movie theater is interested in seeing if female or males, on average, attend the movies a different amount. What is the hypothesis test to be done? (Use u, - H,, where u, is males and u, is females.) O Ho: Hq = Hz O Ho: H, = 0.25 H1: H, = 0.75 O Ho: Hq = H2 O Ho: Hq> Hz B (b) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 90% confidence level. (Round your t-statistic and p-value to four decimal places. Round your critical value to three decimal places.) (Use 4, - Hz, where 4, is males and #z is females.) t-statistic critical value p-value B (c) At a 90% confidence level, should the null hypothesis be accepted or rejected? Fill in the blanks. The null hypothesis should -Select--- . The number of times, on average, that females and males attend the movies each year ---Select-- V statistically different. O (d) Assume the population (all people) standard deviation is known to be four movies per year each for males and females. What are the new test statistic and critical value for a 90% confidence level? (Round your answers to three decimal places.) test statistic critical value You may need to use the appropriate table in the Appendix of Tables to answer this question.

B (a) A movie theater is interested in seeing if female or males, on average, attend the movies a different amount. What is the hypothesis test to be done? (Use u, - H,, where u, is males and u, is females.) O Ho: Hq = Hz O Ho: H, = 0.25 H1: H, = 0.75 O Ho: Hq = H2 O Ho: Hq> Hz B (b) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 90% confidence level. (Round your t-statistic and p-value to four decimal places. Round your critical value to three decimal places.) (Use 4, - Hz, where 4, is males and #z is females.) t-statistic critical value p-value B (c) At a 90% confidence level, should the null hypothesis be accepted or rejected? Fill in the blanks. The null hypothesis should -Select--- . The number of times, on average, that females and males attend the movies each year ---Select-- V statistically different. O (d) Assume the population (all people) standard deviation is known to be four movies per year each for males and females. What are the new test statistic and critical value for a 90% confidence level? (Round your answers to three decimal places.) test statistic critical value You may need to use the appropriate table in the Appendix of Tables to answer this question.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Report Oneway Analysis of Movies in Last Year By Gender Oneway Analysis of Movies in Last Year By Gender Pooled t Test 25 Summary of Fit Rsquare 0.053085 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) 0.028188 4.658185 9.025 40 10- t Test M-F Assuming equal variances M Difference 2.1500 t Ratio 1.459559 Gender Std Err Dif 1.4730 DF 38 Upper CL Dif 5.1320 Prob > |E| 0.1526 Lower CL Dif -0.8320 Prob > t 0.0763 Pooled t Test Confidence 0.95 Prob <t 0.9237 Summary of Fit Analysis of Variance Rsquare 0.053085 Source DF Sum of Squares Mean Square F Ratio Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) 0.028188 4.658185 Gender 1 46.22500 46.2250 2.1303 9.025 Error 38 824.55000 21.6987 40 C. Total 39 870.77500 t Test Means for Oneway Anova M-F Level Number Mean Std Error Lower 95% Uppe Assuming equal variances 20 8.8500 1.0416 6.7414 M 20 11.0000 1.0418 8.8014 2.1500 t Ratio 1.4730 DF 4.6335 Prob > |t| Difference 1.459559 Std Err Dif 38 Std Error uses a pooled estimate of error variance Upper CL Dif 0.1526 Lower CL Dif -0.3335 Prob >t 0.0763 t Test Confidence 0.9 Prob <t 0.9237 -2 M-F Assuming unequal variances 2.1500 t Ratio 1.4730 DF 5.1325 Prob > |E| Difference 1.459550 Analysis of Variance Std Err Dif 37.80348 Upper CL Dif 0.1527 Source DF Sum of Squares Mean Square FRatio Prob >F Lower CL Dif -0.8325 Prob > t 0.0763 Gender 1 46.22500 46.2250 2.1303 0.1526 Confidence 0.95 Prob <t 0.9237 Error 38 824.55000 21.6987 C. Total 39 870.77500 Means for Oneway Anova Level Number Mean Std Eror Lower 90% Upper 90% 20 8.8500 1.0416 7.0939 10.608 M 20 11.0000 1.0416 9.2439 12.750 Std Error uses a pooled estimate of error variance t Test M-F Assuming unequal variances 2.1500 t Ratio 1.4730 DF 4.6338 Prob > |t| Lower CL Dif -0.3338 Prob >t 0.9 Prob <t 1.459550 37.80348 Difference Std Err Dif Upper CL Dif 0.1527 0.0763 Confidence 0.9237 -2 0 II .. Movies in Last Year
Transcribed Image Text:Report Oneway Analysis of Movies in Last Year By Gender Oneway Analysis of Movies in Last Year By Gender Pooled t Test 25 Summary of Fit Rsquare 0.053085 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) 0.028188 4.658185 9.025 40 10- t Test M-F Assuming equal variances M Difference 2.1500 t Ratio 1.459559 Gender Std Err Dif 1.4730 DF 38 Upper CL Dif 5.1320 Prob > |E| 0.1526 Lower CL Dif -0.8320 Prob > t 0.0763 Pooled t Test Confidence 0.95 Prob <t 0.9237 Summary of Fit Analysis of Variance Rsquare 0.053085 Source DF Sum of Squares Mean Square F Ratio Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) 0.028188 4.658185 Gender 1 46.22500 46.2250 2.1303 9.025 Error 38 824.55000 21.6987 40 C. Total 39 870.77500 t Test Means for Oneway Anova M-F Level Number Mean Std Error Lower 95% Uppe Assuming equal variances 20 8.8500 1.0416 6.7414 M 20 11.0000 1.0418 8.8014 2.1500 t Ratio 1.4730 DF 4.6335 Prob > |t| Difference 1.459559 Std Err Dif 38 Std Error uses a pooled estimate of error variance Upper CL Dif 0.1526 Lower CL Dif -0.3335 Prob >t 0.0763 t Test Confidence 0.9 Prob <t 0.9237 -2 M-F Assuming unequal variances 2.1500 t Ratio 1.4730 DF 5.1325 Prob > |E| Difference 1.459550 Analysis of Variance Std Err Dif 37.80348 Upper CL Dif 0.1527 Source DF Sum of Squares Mean Square FRatio Prob >F Lower CL Dif -0.8325 Prob > t 0.0763 Gender 1 46.22500 46.2250 2.1303 0.1526 Confidence 0.95 Prob <t 0.9237 Error 38 824.55000 21.6987 C. Total 39 870.77500 Means for Oneway Anova Level Number Mean Std Eror Lower 90% Upper 90% 20 8.8500 1.0416 7.0939 10.608 M 20 11.0000 1.0416 9.2439 12.750 Std Error uses a pooled estimate of error variance t Test M-F Assuming unequal variances 2.1500 t Ratio 1.4730 DF 4.6338 Prob > |t| Lower CL Dif -0.3338 Prob >t 0.9 Prob <t 1.459550 37.80348 Difference Std Err Dif Upper CL Dif 0.1527 0.0763 Confidence 0.9237 -2 0 II .. Movies in Last Year
O (a) A movie theater is interested in seeing if female or males, on average, attend the movies a different amount. What is the hypothesis test to be done? (Use u, - Hg, where u, is males and u, is females.) O Ho: H1 = H2 O Ho: H, = 0.25 H1 42 = 0.75 O Ho: H1 = H2 O Ho: H1> H2 O (b) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 90% confidence level. (Round your t-statistic and p-value to four decimal places. Round your critical value to three decimal places.) (Use u, - lg, where u, is males and u, is females.) t-statistic critical value p-value O (c) At a 90% confidence level, should the null hypothesis be accepted or rejected? Fill in the blanks. The null hypothesis should ---Select-- . The number of times, on average, that females and males attend the movies each year ---Select-- v statistically different. (d) Assume the population (all people) standard deviation is known to be four movies per year each for males and females. What are the new test statistic and critical value for a 90% confidence level? (Round your answers to three decimal places.) test statistic critical value You may need to use the appropriate table in the Appendix of Tables to answer this question.
Transcribed Image Text:O (a) A movie theater is interested in seeing if female or males, on average, attend the movies a different amount. What is the hypothesis test to be done? (Use u, - Hg, where u, is males and u, is females.) O Ho: H1 = H2 O Ho: H, = 0.25 H1 42 = 0.75 O Ho: H1 = H2 O Ho: H1> H2 O (b) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 90% confidence level. (Round your t-statistic and p-value to four decimal places. Round your critical value to three decimal places.) (Use u, - lg, where u, is males and u, is females.) t-statistic critical value p-value O (c) At a 90% confidence level, should the null hypothesis be accepted or rejected? Fill in the blanks. The null hypothesis should ---Select-- . The number of times, on average, that females and males attend the movies each year ---Select-- v statistically different. (d) Assume the population (all people) standard deviation is known to be four movies per year each for males and females. What are the new test statistic and critical value for a 90% confidence level? (Round your answers to three decimal places.) test statistic critical value You may need to use the appropriate table in the Appendix of Tables to answer this question.
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