(b) At T = 31.0°C, the resistance is given by R = Ro[1 + a(T-To)], where a is the temperature coefficient of resistivity. The current in the copper wire becomes AV Ro[1 + acu(T-To)] I = = AV R = 2.39 M)1 + (3.9 × 10-³ (°C)-¹)( 31.0 Your response differs from the correct answer by more than 100%. °C 7.5 A.

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter28: Current And Resistance
Section28.3: Current Density
Problem 28.3CE
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(a) A 34.6-m length of copper wire at 20.0°C has a radius of 0.28 mm. If a potential difference of 7.50 V is
applied across the length of the wire, determine the current in the wire.
(b) If the wire is heated to 31.0°C while the 7.50-V potential difference is maintained, what is the resulting
current in the wire?
Step 1
(a) From the table below, the resistivity of copper at 20.0°C is Pcu
coefficient of resistivity Cu
have R =
pL/A. Therefore, the resistance Ro of the copper wire at To
=
Ro
=
Pcu
A
=
PCu²
πr²
-8
1.7 x 10 m with temperature
3.9 x 10-3 (°C)-¹. From the general relation between resistance and resistivity, we
20.0°C is given by the following.
(1.7 x
1.7 x 10-8 m
JU 0.28
m)( 34.6
34.6 m
0.28 x 10-3 m
2
=
2.38
2.39| Ω.
Transcribed Image Text:(a) A 34.6-m length of copper wire at 20.0°C has a radius of 0.28 mm. If a potential difference of 7.50 V is applied across the length of the wire, determine the current in the wire. (b) If the wire is heated to 31.0°C while the 7.50-V potential difference is maintained, what is the resulting current in the wire? Step 1 (a) From the table below, the resistivity of copper at 20.0°C is Pcu coefficient of resistivity Cu have R = pL/A. Therefore, the resistance Ro of the copper wire at To = Ro = Pcu A = PCu² πr² -8 1.7 x 10 m with temperature 3.9 x 10-3 (°C)-¹. From the general relation between resistance and resistivity, we 20.0°C is given by the following. (1.7 x 1.7 x 10-8 m JU 0.28 m)( 34.6 34.6 m 0.28 x 10-3 m 2 = 2.38 2.39| Ω.
Step 2
When a 7.50-V potential difference is applied across the length of this wire at 20.0°C, the resulting current Io
is
Io
I =
=
AV
Ro
II
AV
R
7.50
Step 3
=
(b) At T = 31.0°C, the res tance is given by R
resistivity. The current in the copper wire becomes
2.39
2.39
7.5 V
2.39| Ω
AV
Ro[1 + acu(T - To)]
A.
3.13
7.5
3.14 A.
Ro[1 + a(TTO)], where a is the temperature coefficient of
v)
Ω 1 + (3.9 x 10-³ (°C)-¹)(
31.0
Your response differs from the correct answer by more than 100%.°
Transcribed Image Text:Step 2 When a 7.50-V potential difference is applied across the length of this wire at 20.0°C, the resulting current Io is Io I = = AV Ro II AV R 7.50 Step 3 = (b) At T = 31.0°C, the res tance is given by R resistivity. The current in the copper wire becomes 2.39 2.39 7.5 V 2.39| Ω AV Ro[1 + acu(T - To)] A. 3.13 7.5 3.14 A. Ro[1 + a(TTO)], where a is the temperature coefficient of v) Ω 1 + (3.9 x 10-³ (°C)-¹)( 31.0 Your response differs from the correct answer by more than 100%.°
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