(b) Calculate the line voltage (in kV) at bus B and the complex power at the sending end of the transmission line.
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- Figure 3.32 shows the oneline diagram of a three-phase power system. By selecting a common base of 100 MVA and 22 kV on the generator side, draw an impedance diagram showing all impedances including the load impedance in per-unit. The data are given a follows: G:90MVA22kVx=0.18perunitT1:50MVA22/220kVx=0.10perunitT2:40MVA220/11kVx=0.06perunitT3:40MVA22/110kVx=0.064perunitT4:40MVA110/11kVx=0.08perunitM:66.5MVA10.45kVx=0.185perunit Lines I and 2 have series reactances of 48.4 and 65.43, respectively. At bus 4, the three-phase load absorbs 57 MVA at 10.45 kV and 0.6 power factor lagging.One advantage of balanced three-phase systems over separate singlephase systems is reduced capital and operating costs of transmission and distribution. (a) True (b) FalseIt is stated that (i) balanced three-phase circuits can be solved in per unit on a per-phase basis after converting - load impedances to equivalent Y impedances. (ii) Base values can be selected either on a per-phase basis or on a three-phase basis. (a) Both statements are true. (b) Neither is true. (c) Only one of the above is true.
- The one-line diagram of a three-phase power system is as shown in the figure attached. Impedances are marked in per unit on a 100-MVA, 400-kv base. The load at bus 2 is S(sub 2) = 15.93 MW - j33.4 Mvar, and bus 3 is S(sub 3) = 77MW + j14 Mvar. I tis required to hold the voltage at bus 3 at 400 angle 0 degrees kV. Working in per unit, determine the voltage at buses 2 and 1.1. A 69-kV, three-phase short transmission line is 16 km long. The line has a per phase series impedance of 0.125+j0.4375 Ω per km. Determine the sending end voltage, voltage regulation, the sending end power, and the transmission efficiency when the line delivers (a) 70 MVA, 0.8 lagging power factor at 64 kV. (b) 120 MW, unity power factor at 64 kV. Use lineperf program to verify your results. 2. A three-phase, 765-kV, 60-Hz transposed line is composed of four ACSR, l,431,000-cmil, 45/7 Bobolink conductors per phase with flat horizontal spacing of 14 m. The conductors have a diameter of 3.625 cm and a GMR of 1.439 cm. The bundle spacing is 45 cm. The line is 400 km long, and for the purpose of this problem, a lossless line is assumed. (a) Determine the transmission line surge impedance Zc, phase constant ß, Wavelength, the surge impedance loading SIL, and the ABCD constant. b) The line delivers 2000 MVA at 0.8 lagging power factor at 735 kV. Determine the sending end quantities and…Which termination would result to a phase change of 180 degrees at the load if Zo = 100 ohm? a. 50 ohm b. short circuit c. 75 ohm d. all of these What is the purpose of impedance matching? a. maximum return loss b. maximum SWR c. maximum load power d. maximum reflection A short piece of transmission line that may be open or shorted and used for impedance matching purposes. a. converter b. decoder c. stub d. transformer
- Q1: The parameters of a three-phase line 200 km long are resistance/km-0.15 0, inductivekm -0.5 and capacitive susceptancekm-2x 10° U. The transmission line is delivering 50 MVA at 132 kV with power factor 0.85 lagging. Use nominal T method to determine; 1) sending end voltage 2) sending end current 3) sending end power factor 4) transmission efficiency and 5) voltage (4 points) regulationIn the above figure, a single line model of a three-phase power system is given. Base power 50MVA, base voltage 13.8kV according to its value, a) Per-unit values of power system circuit elements according to the given base power and base voltage values. calculate. b) The perunit you calculate by drawing the equivalent impedance circuit for one phase of the power system given in the figure. show on the values.The single line diagram of a power system is shown below. Load represented as impedance, (13.2) kV voltage It draws 60 MVA power from the system when it is below and (0.9) back power factor. Generators and transformers The related electrical parameters are given below. According to this; a) Calculate all impedances in this given circuit in pu and draw the equivalent impedance diagram of the circuit. (Select the base values as 100 MVA and 13.8 kV.) b) Since the voltage values of the generators are given as E1=1.1∟0° pu and E2=1.25∟10° pu, Calculate the value of the voltage (V1).
- Shown are two buses connected via a transmission line. Connected to Bus 1 is a generator(modelled as a voltage source V1), and to Bus 2 is a generator( with Voltage V2) and a load. The line impedance Z = R + jX is not known. Three-phase load is forecasted as 100MW + 60MVar. Generator at Bus 2 is scheduled to deliver 40MW and its excitation is adjusted for the machine to deliver 55 MVar. Voltage at Bus 1 is 241 KV angle 10 deg, while voltage at bus is 230 kV; use V2 as the reference for all angles. 1. What is the current (RMS) in amperes drawn by the load connected to Bus 2? 2. How much real power (in MW) is delivered by the generator connected to Bus 1? 3. What is the total real power loss along the line, in percent of the load? 4. What is the X/R Ratio of the line impedance?The three-phase power and line-line ratings of the electric power system shown in Figure-1 are given below: G1:82 MVA 30 kV X=10% T1:72MVA 30/300 kV X=11% T2:72MVA 300/30 kV X=11% M:62MVA 25 kV X=9% 300 kV Z= 89+j179 Apply the knowledge of per unit system on above network and draw an impedance diagram showing all impedances in per unit when Sb =100MVA and Vb = 30 kvTwo synchronous machines are connected through three phase transformer to the transmission line as given in Fig. The ratings and reactance’s of the machines and transformers are: Machines 1 and 2: 100 MVA; 20 kV; Xd”=X1=X2=20%; X0 = 4%; Xn= 5% Transformers T1 and T2 : 100MVA; 20 / 345 kV ; X=8% The line reactance’s are X1=X2= 15% and X0=50%. The system is operating at nominal voltage without prefault currents when a single line to ground fault occurs on the phase ‘a’ at bus 3 with fault impedance (Zf ) 0.8 p.u. Determine the subtransient current to ground at the fault and draw the sequence network.