(b) Find the value of the following integrals: z-1 1- dz, y is the triangle with vertices at the points z =-51, (z' +z-2) z 31, z 2. %3D -7 2-2 sec z dz,y is the triangle with vertices at the points z - 5. z=--i, z=i.

Q: 2. VI-x² !! 1 dy dx- dz 0 -1V1-x2

A: Change Cartesian coordinate to cylindrical coordinate by using x = r cos(theta) y = r sin(theta) z =…

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Q: + 6) dy dx = t) Evaluate the iterated integral

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Q: 9-x2 C: Change to polar and evaluate the double integrals S (x3 + xy?)dydx V9-x2

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Q: 16–x² Choose the iterated integral that is equivalent to y dy dx in polar coordinates.

A: let x=rcosθ and y=rsinθ dydx=rdrdθydydx=r2sinθdrdθ 16-x2=yx2+y2=42=r2 r=4 Therefore r varies from 0…

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