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- Consider the following common emitter amplifier: Discuss the LIMITATIONS of this circuit in terms of linearity and in terms of impedance matching. I just need the constraints of the circuit, like for example the operating point of the transistor and more.In the images, the graphics are:With the number 1: input-output curveThen a simulation was performed and obtained:With number 2: input-output curveWith number 3: more detailed input-output curveWith number 4: input-output curvePlease I just need the limitations of the circuit based on these graphs.DESIGN AND SIMULATION OF A TWO-STAGE TRANSISTORAMPLIFIER USING UTILIZING LTSPICE I. Circuit Design Schematic with component ValuesDraw the dc and ac equivalent circuits (menu steps 1 and 3) for the common-source amplifier as shown .
- Design a Single-Stage Common Emitter Class A Amplifier Specifications:Voltage Divider Bias Circuit Supply: Any value from 10Vdc to 24VdcLoad: 1kΩVoltage Gain: Any value from 80 to 400Lower Cutoff Frequency: 100 HzSinusoidal source (zero internal resistance): 50mVp-pTransistor: Si, β = 75 • Base-Collector capacitance = 8pF • Base-Emitter Capacitance = 25pF a) compute for the biasing resistances.b) determine the dc transistor terminal voltages and transistor currents.1. Consider a common emitter amplifier. If the collector current at saturation is 10 mA and the cutoff voltage is 9V, what should be the coordinates of the operating point for: a) Class A amplifier b) Class B amplifier Please show the complete solution. Thank you !1.What is the difference between bipolar junction transistor and field effect transistor? Explain this in your word. 2.What is the significance of bypass capacitor in the amplifier circuit? Explain this in your word.
- b)The transistor consists of three terminals. The main reason for designing configurations is that it requires four terminals in order to provide the input and the output connections of the circuit for effective amplification. Now in your own words describe how Bipolar Transistors Transistor ( BJT ) various configurations are designed with relating diagrams. In your own estimation evalute which one is most widely used when looking at appreciable output for an amplifier?Question 1: Draw and explain the transistor amplifier, which is usually referred as emitter follower.Also, (i) derive its voltage and current gains by equivalent circuit; (ii) compare its voltage and current gains with other transistor amplifiers. Question 2:(a) Predict the name of the curve drawn between ID and VGS of the JFET and represent the cut off voltage in it. (b) E-MOSFET has ID(on) = 600mA (minimum) at VGS = 9V and VGS(th) = 1 V. Find the drain current for VGS = 6 V. Question 3: (a) State the name of the power amplifier, which has a efficiency as 10% in practical case and also derive and prove its theoretical efficiency is 25%. (b) Explain the role of Q point in power amplifiers based on its location in AC load line.…There is a requirement to design a transistor amplifier circuit which gives a voltage amplification of 25dB. What are the further details that you as a designer require in order to complete the design process? If the input to the amplifier above is , what is the output? Sketch a suggested configuration for the amplifier circuit and plot both input and output signals on the same axes.
- Consider the following common emitter amplifier: Please, discuss the LIMITATIONS of this circuit in terms of linearity and in terms of impedance matching.1. Use the figure below to solve following questions (a) Solve the following dc quantitiesi. VB(Q1)ii. VE(Q1)iii. IE(Q1)iv. VC(Q1)v. VB(Q2)vi. VE(Q2)vii. IE(Q2)viii. VC(Q2)(b) Suppose that the emitter follower is omitted and the output from thecollector of Q1 is capacitively coupled to the 250Ω load, RL. What isthe output voltage across the 250Ω load?The dc bias circuit for a common emitter amplifier is shown in the figure. In the circuit, Vcc=15v,RB1=20k Ω,RB2=100k Ω,Rc=5.1k Ω,and RE1=1k Ω, Assume that when the transistor is on, the voltage drop from base to emitter VBE=0.7v. Also assume that β= ∞, which implies that the base current can be considered zero (IB=0) in your calculations. Solve for the base voltage VB. Solve for the emitter voltage VE. Solve for the emitter current IB. Solve for the collector current IC