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- A newly synthesized drug was found to have a carboxyl group, an imide and a sulfonamide group. The first type of method to consider in this drug molecule’s quantitatve analysis is: a. Non-aqueous Alkalimetryb. Non-aqueous Acidimetryc. Aqueous Alklaimetryd. Aqueous AcidimetryGive and observation and inference when the compound hexane is subjected into test for Br2 in CCl4Data: Density of p-phenetidine is 1.065g/mol Williamson Ether Synthesis: Mass of filter paper: 0.680 g Mass of filter paper and product: 1.482 g Melting Point: 134-136oC Amide Synthesis: Mass of filter paper: 0.686 g Mass of filter paper and product: 1.589 g Melting Point: 135-137oC Mixed Melting Point (product of amide synthesis mixed with Williamson Ether synthesis product): 134-136oC (a)Calculate theoretical yield of both williamson ether synthesis of phenacetine and amide synthesis of phenacetin. (b) calculate the percent yield of phenacetin obtained via williamson ether synthesis. (c) Calculate the percent yeild of phenacetin obtained via the amide synthesis.
- The ethyl mercaptan concentration in a mixture was determined by shaking a 2.0430-g sample with 50.00 mL of 0.01204 M I2 in a tightly stoppered flask: 2C2H5SH + I2 ---> C2H5SSC2H5 + 2I- + 2H+ The excess I2 was back-titrated with 18.23 mL of 0.01437 M Na2S2O3. Calculate the percentage of C2H5SH (MW = 62.13 g/mol). Millimoles of excess standard I2 solution is ___ 0.5239 0.3400 0.2620 0.1310 Millimoles of C2H5SH in the sample is ___ . 0.9420 0.6800 0.4710 0.2355 Percentage of C2H5SH in the sample is ___ . 0.72 2.86 2.07 1.43You performed an isocratic reversed-phase HPLC separation of phenol, toluene and catechol using a DAD detector set at 275nm and obtained the chromatogram shown below. What are the polarities of the mobile phase and stationary phase in this separation? What order would you expect these compounds to elute in? Why? What changes could you make to the mobile phase to decrease the elution time of the last compound and improve its peak shape? If all three species are present in the analyzed solution at the same concentration, what might account for different in peak height for the first two compounds eluting from the column? What change to the instrument set-up could you make to increase the detector response of this analyte?All methyl esters of long-chain aliphatic acids (e.g., methyl tetradecanoate, C13H27COOCH3) show significant fragment ions at m/z 74, 59, and 31. What are the structures of these ions? How are they formed?
- Introduction qualification and quantification of limonene using gas chromatographic analysisAnnotate the Mass Spec and 13C NMR for C8H8O2 or 4-Methylbenzoic AcidGive a detailed procedure of how you will process 5 samples of palm oil adulterated with Sudan IV dye before analysing it with Raman spectroscopy. Name and state the functions reagents used in the sample processing.
- The molar absorptivity of 2,5-dimethyl-2,4-hexadiene in methanol is 13,100 M-1cm-1. What concentration of this diene in methanol is required to give an absorbance of 1.6? Assume a light path of 1.00 cm. Calculate concentration in these units. Q.) Moles per literWhat is the limiting reagent in the synthesis of triphenylmethanol via Grignard reagent? Show the calculation briefly and prove it Compound MW starting mass or volume Density mmol Magnesium 24.31 0.538 1.74 22.0mmol Bromobenzene 157.01 2.4mL 1.495 22.0mmol Benzophenone 182.2 3.651mL 20.0mmolThis is an illustration of TLC plates. The compounds used were syn-azobenzene (A) and anti-azobenzene (B). The difference between the two plates are that the first was placed in 15% methylene chloride in pet. ether and the second was placed in 30% methylene chloride in pet. ether. I calculated Rf values to be 0.47 mm for syn-azobenzene and 0.44 mm for anti-azobenzene in 15% while syn-azobenze had a Rf of 0.28 mm and 0.16 mm. Which solvent is best at separating and how does Rf help identify which isomer is which? I read that the anti is supposed to have a higher Rf but that is not the case here so I want to know if the syn is supposed to have the higher Rf and the anti is supposed to have the lower one.