1:3228. Centroid. *a. 7.35 KN (Downward Direction)b. 7.37 KN (Downward Direction)c. 7.35 KN (Upward Direction)d. 7.37 KN (Upward Direction)29. Shear force equation for segment AB. *a. 0.49KN-0.15x2 (KN/m2)b. 0.49KN-0.16x2 (KN/m2)c. 0.58KN-0.18x2 (KN/m2)d. 0.58KN-0.19x2 (KN/m2)30. Bending moment equation forsegment AB.a. 0.58x(KN)-0.16x3(KN/m2)b. 0.58x(KN)-0.26x3(KN/m2)c. 0.49x(KN)-0.07x3(KN/m2)d. 0.49x(KN)-0.05x3(KN/m2)Ο ΟOO* () ** | | 56% -O B. Derive the shear forceequation,bendingmoment equation forthe beam shown. Neglect the weight ofthe beam.2.1 kN/mCB5 m-Determine the following:26. Reaction support at point A.-2m-

Answer: 26. Reaction support at point A: 0.49 kN 28. Centroid: 7.35 (Downward direction) ...Option…

Answered: B. Derive the shear force…

B. Derive the shear force equation,bending moment equation for the beam shown. Neglect the weight of the beam. 2.1 kN/m A C B Determine the following: 26. 5 m Reaction support at point A. 2 m. *

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Bending Moment

In general, we can define the bending moment as the reaction induced when a certain amount of load or force is applied to an element which makes it bend.

Question

1:32
28. Centroid. *
a. 7.35 KN (Downward Direction)
b. 7.37 KN (Downward Direction)
c. 7.35 KN (Upward Direction)
d. 7.37 KN (Upward Direction)
29. Shear force equation for segment AB. *
a. 0.49KN-0.15x2 (KN/m2)
b. 0.49KN-0.16x2 (KN/m2)
c. 0.58KN-0.18x2 (KN/m2)
d. 0.58KN-0.19x2 (KN/m2)
30. Bending moment equation for
segment AB.
a. 0.58x(KN)-0.16x3(KN/m2)
b. 0.58x(KN)-0.26x3(KN/m2)
c. 0.49x(KN)-0.07x3(KN/m2)
d. 0.49x(KN)-0.05x3(KN/m2)
Ο Ο
O
O
* () ** | | 56% -
O

B. Derive the shear force
equation,bending
moment equation for
the beam shown. Neglect the weight of
the beam.
2.1 kN/m
C
B
5 m-
Determine the following:
26. Reaction support at point A.
-2m-

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