b. Perform first five iterations of the following sorting algorithm on the above ASCIII numbers. def Sort(A): for į in range(len(A)): idx = i for j in range(i+1, len(A)): if Alidx) < A[j]: idx = j A[i), A[idx) = A[idx], A[i]
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USE PYTHON
SOLVE ONLY B PART
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Solved in 2 steps
- 1(a) Create an eight-digit binary number containing a point. This eight-digit binary number must contain at least four l's with two digits after the point. Convert to denary.Do some research to find at least two characters in the Extended ASCII character set, and the keyboard shortcuts that allow you to enter those characters directly from the keyboard. If possible, the characters should include letters in your name from question 1, otherwise add some new characters. Type the characters, AND the shortcuts you used. For example: Jôhn Bénoït (option-i, o), (option-e, e), (option-u, i).10. Examine the following code segment. What will be printed? If there are any errors indicate the nature of the error. int a[9] = { 1, 12, 3, 14, 25, 16, 7, 8, 9 }; int *ptr ; ptr = & a[ 2 ] ; for( i = 1; i <= 5; i = i + 2) cout << a[i] << *( ptr + i ); cout << ” ” << a[0] << ” ” << *ptr << ” ” << *ptr - 1 << ” ” << *(ptr - 2));
- 5. Using the Max function, write a formula in cell F7 of Top10_Pivot Sheet to find the maximum "Sum of Percentage" value. Do not select the Grand Total range in the function.6. Using the MATCH function only, write a formula in cell G7 of Top10_Pivot Sheet to find the Row Number of Maximum Sum of percentage.7. Using the INDEX function only, write a formula in cell H7 to find the state name having the maximum "Sum of Percentage". The formula should include the value(row number) that is calculated in G7.There are errors in lines 56 and 57. Please fix those errors and show the fixed code.2.30 LAB: Phone number breakdown CODE C Given a long long integer representing a 10-digit phone number, output the area code, prefix, and line number using the format (800) 555-1212. Ex: If the input is: 8005551212 the output is: (800) 555-1212 Hint: Use the modulo operator (%) to get the desired rightmost digits. Ex: The rightmost 2 digits of 572 is gotten by 572 % 100, which is 72. Hint: Use / to shift right by the desired amount. Ex: Shifting 572 right by 2 digits is done by 572 / 100, which yields 5. (Recall integer division discards the fraction). For simplicity, assume any part starts with a non-zero digit. So 0119998888 is not allowed. LAB ACTIVITY 2.30.1: LAB: Phone number breakdown #include <stdio.h> int main(void) { longlongphoneNumber; /* Add more variables as needed */ scanf("%lld",&phoneNumber); /* Type your code here. */ return0; } Develop modeSubmit mode
- Please code in C++ to accept any word and print last letterUsing PIC18F1220 write code to manipulate ASCII codes to change between uppercase and lowercase. Use thefollowing rules, based on each character’s ASCII code:1) if >= 0x41 and <= 0x5A, add 0x20 to make lowercase2) if >=0x61 and <= 0x7A, subtract 0x20 to make uppercaseThe first question: write a code segment to print the numbers between 2 to 20 that are divisible by 4 without remainder