List the resulting array after each iteration of the outer loop of the insertion sort algorithm. Indicate the number of character-to-character comparisons made for each iteration (line 06 of the Insertion Sort algorithm). Sort the following array of characters into alphabetical order: C QRBPDX. 01 public static void insertionSort (char[] a) { 02 int n = a.length; for ( int i = 1; i < n; i++ ) { for ( int j if ( a[j-1] > a[j] ) { exchange (a, j-1, j); } else break; } 03 %3D 04 05 = i; j > 0; j-- ) { 06 07 08 09 10 } 11 12 private static void exchange (char [] a, int i, int j) { 13 // exchange the value at index i with the value at index j 14 char temp = a[i]; 15 a[i] alj]; %3D a[j] } 16 temp; %3D 17

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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java

List the resulting array after each iteration of the outer loop of the insertion sort algorithm.
Indicate the number of character-to-character comparisons made for each iteration (line 06 of
the Insertion Sort
algorithm). Sort the following array of characters into alphabetical order: CQRB PDX.
01 public static void insertionSort (char[] a) {
02
int n = a.length;
for ( int i = 1; i < n; i++ ) {
for ( int j
if ( a[j-1] > a[j] ) {
exchange (a, j-1, j);
} else break;
03
04
05
= i; j > 0; j-- ) {
06
07
08
09
}
10
}
11
12 private static void exchange (char [] a, int i, int j) {
// exchange the value at index i with the value at index j
13
14
char temp
a[i];
15
a[i]
a[j];
a[j]
}
16
temp;
17
Enter your answer here
Transcribed Image Text:List the resulting array after each iteration of the outer loop of the insertion sort algorithm. Indicate the number of character-to-character comparisons made for each iteration (line 06 of the Insertion Sort algorithm). Sort the following array of characters into alphabetical order: CQRB PDX. 01 public static void insertionSort (char[] a) { 02 int n = a.length; for ( int i = 1; i < n; i++ ) { for ( int j if ( a[j-1] > a[j] ) { exchange (a, j-1, j); } else break; 03 04 05 = i; j > 0; j-- ) { 06 07 08 09 } 10 } 11 12 private static void exchange (char [] a, int i, int j) { // exchange the value at index i with the value at index j 13 14 char temp a[i]; 15 a[i] a[j]; a[j] } 16 temp; 17 Enter your answer here
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