b. The distance traveled between t=0 and t= 10. 0- c. The position at t= 10. d. A piecewise function for s(t). 10 -5- a. The displacement is 18 m. (Simplify your answer.) b. The distance traveled between t = 0 and t= 10 is 26 meters. (Simplify your answer.) c. The position at t= 10 is 18 m. (Simplify your answer.) d. Choose the correct answer below. O A. O B. 21? Osts1 212 Osts1 - 2t + 8t-4 - 21 + 1

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter3: Motion Along A Straight Line
Section: Chapter Questions
Problem 46P: (a) Sketch a graph of velocity versus time corresponding to the graph of displacement versus time...
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Question
The figure shows the velocity function for motion along a
line. Assume the motion begins with an initial position of
s(0) = 0. Determine the following.
a. The displacement between t= 0 and t= 10.
b. The distance traveled between t 0 and t= 10.
c. The position at t= 10.
d. A piecewise function for s(t).
Av (m/sec)
5
t (sec)
0-
4
10
-5-
a. The displacement is 18 m.
(Simplify your answer.)
b. The distance traveled between t = 0 and t= 10 is 26 meters.
(Simplify your answer.)
c. The position at t= 10 is 18 m.
(Simplify your answer.)
d. Choose the correct answer below.
O A.
O B.
212
Osts1
212
Osts1
- 212 + 8t - 4 1<ts3
212.
+ 8t- 4 1<ts3
s(t) = { 2 - 16t + 32 3<t5
s(t) = 3-+20t - 82 3<ts5
4t 18
5<ts8
4t 18
5<ts8
-t+20t - 82 8<ts 10
2t - 16t + 32 8<ts 10
Transcribed Image Text:The figure shows the velocity function for motion along a line. Assume the motion begins with an initial position of s(0) = 0. Determine the following. a. The displacement between t= 0 and t= 10. b. The distance traveled between t 0 and t= 10. c. The position at t= 10. d. A piecewise function for s(t). Av (m/sec) 5 t (sec) 0- 4 10 -5- a. The displacement is 18 m. (Simplify your answer.) b. The distance traveled between t = 0 and t= 10 is 26 meters. (Simplify your answer.) c. The position at t= 10 is 18 m. (Simplify your answer.) d. Choose the correct answer below. O A. O B. 212 Osts1 212 Osts1 - 212 + 8t - 4 1<ts3 212. + 8t- 4 1<ts3 s(t) = { 2 - 16t + 32 3<t5 s(t) = 3-+20t - 82 3<ts5 4t 18 5<ts8 4t 18 5<ts8 -t+20t - 82 8<ts 10 2t - 16t + 32 8<ts 10
Expert Solution
Step 1

Distance will be the total area under velocity vs time graph

Whereas displacement is the net area under the velocity vs time graph

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