Based on the amplifier given in Fig. 2, draw the small signal equivalent and derive the two time constants associated with capacitances C1 and C2. Assume early voltage is infinity. Finally, indicate which formula out of the two should be used for the lower 3 dB frequency calculation? Formulate the maximum gain. I need help solving this problem. I asked a similar question
Power Amplifier
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Maximum Efficiency Criterion
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Based on the amplifier given in Fig. 2, draw the small signal equivalent and
derive the two time constants associated with capacitances C1 and C2. Assume
early voltage is infinity. Finally, indicate which formula out of the two should be
used for the lower 3 dB frequency calculation? Formulate the maximum gain.
I need help solving this problem. I asked a similar question before but after trying to get some clarification on my values and my instructor said that it was incorrect. The values that I have attached as screenshots. Is there something wrong with the math. The main issue that came up is the value for the time constant for C1.
![-Vth + RthlB + VBE + R4le = 0
-Vth + RthlB + VBE + R₁(1 + B)IB = 0
Vth - VBE
Rth + (1+B)R4
IB =
0.82V - 0.7V
.91k + (1 + 100)47
Ic = BIB Ic= 0.0212m x 100 → Ic= 2.121mA
IB =
VT
1π = →=
Ic
IB 0.0212mA
0.026V
2.121mA
T= 12.260
T₁ = C₁Req1
T₁ = C₁ x ([Rth ||{ßr + (1 +ß)R₁}] + 100)
T₁ = 1μ × ([0.91k||{100(12.26) + (1 + 100) × 47}] + 100)
T₁ = 1μ x {0.79k + 0.1k} → T₁ = 8.9 x 10-4sec
T₂ = C₂Req2
T2
10μ x {R3 + R5}
T₂ = 10μ x {1.5k + 100k
T₂
1.015sec
0.79k
0.79k + 0.1k
Vin = 1.126Vp → Vin = 1.126 x 5.973kib → Vin = 6.7kib
V₂ =
X Vin
Vout = -(1.5k||100k)ẞib → Vout= -1.48kẞi,
-1.48ßib
6.7kip
→ Ay = -22.1
Vout
Ay = → Ay =
Vin](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe98a1032-a540-4c11-9a72-2e59a7d74a4e%2Fd38d3373-b072-43ba-8397-eb31547a83d1%2F4sr3ctm_processed.png&w=3840&q=75)
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