Based on the fingerprint, do you think Son and Father were independently infected by L. monocytogenes from two different sources, or from the same source? Explain your answer in simplest terms
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Based on the fingerprint, do you think Son and Father were independently infected by L. monocytogenes from two different sources, or from the same source? Explain your answer in simplest terms
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- fungus Aspergillus sydowii Write a short summary (4 paragraphs) about fungus Aspergillus sydowii using all four resources.please add the citations within the text. 1) Presence of Aspergillus sydowii, a pathogen of gorgonian sea fans in the marine sponge Spongia obscura N Ein-Gil, M Ilan, S Carmeli, GW Smith, JR Pawlik… - The ISME …, 2009 2) Purification and Biochemical Characterization of Two Xylanases from Aspergillus sydowii SBS 45 SG Nair, R Sindhu, S Shashidhar - Applied biochemistry and …, 2008 3) Biotechnological potential of a novel tannase-acyl hydrolase from Aspergillus sydowii using waste coir residue: Aqueous two-phase system and chromatographic … KKSA Albuquerque, WWC Albuquerque… - Biocatalysis and …, 2020 4) Aspergillus sydowii: Genome Analysis and Characterization of Two Heterologous Expressed, Non-redundant Xylanases SC Brandt, B Ellinger, T Van Nguyen… - Frontiers in …, 2020Please do not give solution in image format thanku The desired final population of a microbial population is a probability of 0.00058. If the initial population is 5 x10^4 and the survival of the population is described by a D(subscript)121=1.5 min,and a z=11C,estimate the time required to reach the desired probability at 110C.A 10-2 is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 61 colonies of bacteria grow on the plate. Assuming each colony came from a single bacterium, how many bacteria are in a single mL of the original culture?
- QUESTION 4The ability of a bacterial isolate to perform hemolysis can be regarded as an indication ofpotential pathogenicity. Briefly describe how you would test for this trait. QUESTION 5You are asked to recommend an antibiotic to treat this infection in an animal. Describe amethod which will allow you to make this recommendation. QUESTION 6The isolate you obtained appears to be very unique. Another laboratory has requested a sampleof the isolate for further research. To transport the isolate, you need to transfer it from an agarplate to a transport media broth. Describe the procedure you would use.Samples: - 1 & 5: Standard proteins (Ladder) - 2 &6: Uncut - 3 & 7: 5 mins - 4 & 8: 30 mins Human and Bovine (Left) Chicken and Pigeon (Right) What do you expect in the lane for #1 tubes? Explain the reason for your expectation. Do the results match the expectations? Do you observe differences in the lanes for tubes 2 and 3? What does that tell you? Are there differences among the species? What does that tell you about how closely related the proteins are from these species? Do the results match the prediction and support the hypothesis? How would your results have been different if an enzyme with a different amino acid sequence preference had been used?Antibiotic Code Zone of Inhibition (mm) S, I, or R? Penicillin P 15 Streptomycin S 8 Ampicillin A 25 Chloramphenicol C 14 Bacitracin B 5 QUESTIONS: Which antimicrobial agent was most effective against your organism? Can you determine from your results whether this antimicrobial agent will also be most effective against another bacterium? Why or why not? Is this technique measuring bacteriostatic effect, bactericidal effects, or both? Explain. 4) Consider the following list of hypothetical antibiotics, tested against Escherichia coli in a Kirby-Bauer test: Antibiotic Zone of Inhibition (mm) Astonostatin 12 Bodaciosporin 25 Crazifloxacin 5 Dorkimycin 16 When the above antibiotics were tested as treatments for E. coli infections in humans, it was found that Dorkimycin has virtually no effect on the infection, while Astonostatin is the most effective of the four antibiotics listed. Propose an explanation for this result. Based purely on these…
- Info:(For Wildtype) Extinction Coefficient BGG: 0.0007 (y = 0.0007x Beer's Law Graph) Extinction Coefficient BSA: 0.0011 (y = 0.0011x Beer's Law Graph) Cell Lysate: ABS: 0.2, BSA Protein: 285.7mM, BGG Protein: 181.8mM Cell Lysate 1 in 5 dilution: ABsorbtion, 0.03, BSA Protein: 214.3mM, BGG Protein: 136.4mM Elution: Abs .03, Protein BSA: 42.9mM, Protein BGG: 27.3mM Elution DIlution 1/5: ABS: 0.005, Protein BSA: 35.7mM, Protein BGG: 22.7mM Problem: 5. Looking at the sequence of the BGG and BSA standards compared to the sequence of MBP-BAP, which ofthe two standards is the better choice for determining the concentration of MBP-BAP. A. What amino acids react with the Bradford reagent? B. Find the % Composition of amino acids that react with Bradford C. Which standard is best for determining the concentration of MBP-BAP? Briefly explain. D. Explain briefly why choosing a specific standard is less important for determining the concentration of proteinin the cell lysate compared to the…You also obtained the MIC for a variety of common antifungals by testing them against a single strain of Aspergillus fumigatis. Six replicates of each were tested. MIC (ug/mL) Amphotericin B 1 Miconazole 0.06 Ciclopirox 0.01 Nystatin 0.625 New product 0.1 Two-way ANOVA Amp v. New 3.70E-04 Nys v. New 4.16E-05 Mico v. New 0.04 Cic vs. New 1.50E-05 Additionally, Candida aurus is a fungus that is rapidly becoming resistant to multiple antifungals. Because strains now exist that are completely resistant to three or more families of antifungals, there is room in the market for an antifungal that is effective against C. aurus. If the data above is representative for the efficacy against both A. fumigatus, a fungus that is plentiful and sensitive to most antifungals, and C. aurus, determine whether this efficacy data supports room for this product on the existing marketplace. If you think more data is required in order to make a final decision about this…A 0.00001 dilution is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 223 colonies of bacteria grow on the petri dish. Assuming each colony came from a single bacterium, how many bacteria are in a single mL of the original culture? Express your answer to two decimal places using exponential notation. Since only 0.1 mL is put on the plate, this counts as an extra dilution!!! Any time less than 1 mL is transfered, a dilution is being performed. Any time more than 1 mL is transfered, a concentration is being performed.
- Hi, I am working on qPCR quantification for specific bacteria. However, when the CT value achieve greater than 30, it always shown high CT value differences in my duplication no matter I repeat the same set of experiment for those samples with low quality. My question is, what makes this happening? The other question is, how many CT value differences is acceptable for duplication?A species of bacteria has a doubling time of 24 hours. After incubating the initial population for one week, the final population was 6,400 cells. What was the initial population of that bacteria? Show all work. Equations: Nt = No x 2n Final concentration = (initial concentration)/(total dilution factor) Total dilution factor = (individual dilution factor)# of serial dilutionsA 10-5 dilution is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 278 colony forming units grow on the plate. How many bacteria are in a single mL of the original culture? Express your answer to two decimal places using scientific notation. In scientific notation 540 would be written as 5.40*10^2. Since only 0.1 mL is put on the plate, this counts as an extra dilution!!! Any time less than 1 mL is transferred, a dilution is being performed. Any time more than 1 mL is transferred, a concentration is being performed. Include the trailing zero so there are two decimal places Canvas expects a single digit before the decimal point. 5.40*10^2 is how Canvas expects 540 to be formatted in scientific notation 54.00*10^1 would be marked wrong. 0.54*10^3 would be marked wrong. A 10-5 dilution is performed on a culture of bacteria in order to perform viable plate counts. From the…