Based on this report (and assuming that none of the compounds significantly increased inflammation), what would you conclude about the 3 compounds and their effectiveness? Which compound(s) would you choose for further study?

Understanding Health Insurance: A Guide to Billing and Reimbursement
14th Edition
ISBN:9781337679480
Author:GREEN
Publisher:GREEN
Chapter12: Commercial Insurance
Section: Chapter Questions
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A group of researchers have isolated three novel compounds from the venom of a newly discovered species of wasp. Based on their structure and protein chemistry, the researchers believe that all three compounds may have strong anti-inflammatory activity and they have devised an experiment to test whether their compounds can reduce muscle damage after exercise. They plan to induce muscle damage in mice by causing repeated eccentric contractions (by running them downhill on a treadmill), and then examine the amount of inflammation in the muscles of their mice 24hrs later. They will use the following treatment groups: 

 

Sample 1) no treatment (control) 

Sample 2) 1mg/kg of Compound ‘A’ 

Sample 3) 1mg/kg of Compound ‘B’, and; 

Sample 4) 1mg/kg of Compound ‘C’. 

 

They perform their experiment and analyse their results using ANOVA followed by a post-hoc test. The results are as follows: (IMAGE ATTACHED)

QUESTION IS: Based on this report (and assuming that none of the compounds significantly increased inflammation), what would you conclude about the 3 compounds and their effectiveness? Which compound(s) would you choose for further study?

Data Summary
Samples
1.
2
4
5
Total
N
6
6
24
ΣΧ
600
597
567
418
2182
Mean
100
99.5
94.5
69.6667
90.9167
ΣΧ?
60000
59419
53587
29234
202240
Variance
3.5
1.1
22.6667
167.8188
Std.Dev.
1.8708
1.0488
4.761
12.9545
Std.Err.
0.7638
0.4282
1.9437
2.6443
standard weighted-means analysis
ANOVA Summary Independent Samples k=4
Source
df
MS
Treatment
3723.5
3
1241.1667
182.08
<.0001
[between groups]
Error
136.3333
20
6.8167
Ss/BI
Graph Maker
Total
3859.8333
23
Ss/BI = Subjects or Blocks depending on the design.
Applicable only to correlated-samples ANOVA.
%3D
Tukey HSD Test
M1 = mean of Sample 1
M2 = mean of Sample 2
HSD[.05]=4.23; HSD[.01]=5.36
M1 vs M2 nonsignificant
M1 vs M3 P<.01
M1 vs M4 P<.01
and so forth.
М2 vs M3 P&.05
HSD = the absolute [unsigned]
difference between any two
sample means required for
significance at the designated
level. HSD[.05] for the .05 level;
HSD[.01] for the .01 level.
M2 vs M4 P<.01
M3 vs M4 P<.01
3.
Transcribed Image Text:Data Summary Samples 1. 2 4 5 Total N 6 6 24 ΣΧ 600 597 567 418 2182 Mean 100 99.5 94.5 69.6667 90.9167 ΣΧ? 60000 59419 53587 29234 202240 Variance 3.5 1.1 22.6667 167.8188 Std.Dev. 1.8708 1.0488 4.761 12.9545 Std.Err. 0.7638 0.4282 1.9437 2.6443 standard weighted-means analysis ANOVA Summary Independent Samples k=4 Source df MS Treatment 3723.5 3 1241.1667 182.08 <.0001 [between groups] Error 136.3333 20 6.8167 Ss/BI Graph Maker Total 3859.8333 23 Ss/BI = Subjects or Blocks depending on the design. Applicable only to correlated-samples ANOVA. %3D Tukey HSD Test M1 = mean of Sample 1 M2 = mean of Sample 2 HSD[.05]=4.23; HSD[.01]=5.36 M1 vs M2 nonsignificant M1 vs M3 P<.01 M1 vs M4 P<.01 and so forth. М2 vs M3 P&.05 HSD = the absolute [unsigned] difference between any two sample means required for significance at the designated level. HSD[.05] for the .05 level; HSD[.01] for the .01 level. M2 vs M4 P<.01 M3 vs M4 P<.01 3.
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