Be sure to answer all parts. Ammonia is produced by the reaction of nitrogen and hydrogen according to the equation N2(g) + 3H2(g) → 2NH3(g) Calculate the mass of ammonia produced when 34.0 g of nitrogen react with 14.8 g of hydrogen.   g NH3 Which is the excess reactant and how much of it will be left over when the reaction is complete?  hydrogen  nitrogen  g

Question
Asked Oct 25, 2019
Be sure to answer all parts.
 
Ammonia is produced by the reaction of nitrogen and hydrogen according to the equation
 
N2(g) + 3H2(g) → 2NH3(g)
 
Calculate the mass of ammonia produced when 34.0 g of nitrogen react with 14.8 g of hydrogen.
 
 
 g NH3
 
Which is the excess reactant and how much of it will be left over when the reaction is complete?
  
hydrogen
  
nitrogen

 
 g
check_circleExpert Solution
Step 1

Given:

Mass of N2 = 34.0 g

Mass of H2 = 14.8 g

N2(g) + 3H2(g) → 2NH3(g)

Step 2

Calculation for number of moles of N2:

mass
number of moles
molar mass
34.0 g
number of moles =
28.0134 g/mol
number of moles = 1.2137 mol
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mass number of moles molar mass 34.0 g number of moles = 28.0134 g/mol number of moles = 1.2137 mol

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Step 3

Calculation for number of mo...

mass
number of moles
molar mass
14.8 g
number of moles
2.01588 g/mol
number of moles
7.3417 mol
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Image Transcriptionclose

mass number of moles molar mass 14.8 g number of moles 2.01588 g/mol number of moles 7.3417 mol

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