Chapter 16 (Due 06/10, 23:00) OSaved3 attempts leftCheck my workBe sure to answer all parts.Consider the following equilibrium process at 686°C:SoCO;(g) + H2(g) = CO(g)+ H2O(g)GuidecThe equilibrium concentrations of the reacting species are [CO] = 0.0500 M, [H2] = 0.0420 M,[CO2] = 0.0900 M, and [H,O] = 0.0350 M.ok(a) Calculate K, for the reaction at 686°C.int(b) If we add CO, to increase its concentration to 0.480 mol / L, what will the concentrations of all thegases be when equilibrium is reestablished?encesCO2:MH,:MCO:MH,O:M< Prev5 of 9Next >МaсВook ProThankWe@#3$4.5.8.CO3.2.

In order to solve this question, law of mass action will be applied to calculate the value of Kc and…

Be sure to answer all parts. Consider the following equilibrium process at 686°C: CO;(g) + H2(g) = CO(g) + H2O(g) The equilibrium concentrations of the reacting species are [CO] = 0.0500 M, (H2] = 0.0420 M, [CO2] = 0.0900 M, and [H,O] = 0.0350 M. %3D (a) Calculate K, for the reaction at 686°C. (b) If we add CO, to increase its concentration to 0.480 mol /L, what will the concentrations of all the gases be when equilibrium is reestablished?

Be sure to answer all parts. Consider the following equilibrium process at 686°C: CO;(g) + H2(g) = CO(g) + H2O(g) The equilibrium concentrations of the reacting species are [CO] = 0.0500 M, (H2] = 0.0420 M, [CO2] = 0.0900 M, and [H,O] = 0.0350 M. %3D (a) Calculate K, for the reaction at 686°C. (b) If we add CO, to increase its concentration to 0.480 mol /L, what will the concentrations of all the gases be when equilibrium is reestablished?

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.115PAE

See similar textbooks

Similar questions

12.108 A nuclear engineer is considering the effect of discharging waste heat from a power plant into a lake and estimates that this may warm the water locally to 25 °C. One question to be considered is the effect of this temperature change on the uptake of CO2 by the water. The equilibrium constant for the reaction CO2+H2OH2CO3 ; is K=1.7103 at 25 °C. Because bonds form, the reaction is exothermic. (a) Will this reaction progress further toward products at higher temperatures near the water discharge with its warmer water than it would in the cooler lake water? Explain your reasoning. (b) Carbonic acid has a Kaof 2.5104 at 25 °C. What is the equilibrium constant for the CO2+2H2OHCO3+H3O+? (c) What additional factor should the engineer be considering about CO2 gas, probably before considering this reaction chemistry?
Hydrogen gas and iodine gas react to form hydrogen iodide. If 0.500 mol H2 and 1.00 mol I2 are placed in a closed 10.0-L vessel, what is the mole fraction of HI in the mixture when equilibrium is reached at 205C? Use data from Appendix C and any reasonable approximations to obtain K.
. At high temperatures, elemental nitrogen and oxygen react with each other to form nitrogen monoxide. N2(g)+O2(g)2NO(g)Suppose the system is analyzed at a particular temperature, and the equilibrium concentrations arc found to be [N2]=0.041M. [O2]=0.0078M, and [NO]=4.710M. Calculate the value of K for the reaction.
In a particular experiment, the equilibrium constant measured for the reaction, Cl2(g)+NO2(g)Cl2NO2(g), is 2.8. Based on this measurement, calculate AG° for this reaction. Calculate AG° using data from Appendix E at the back of the book and discuss the agreement between your two calculations.
The following data were collected for a system at equilibrium at 140°C. Calculate the equilibrium constant for the reaction, 3 H2(g) + N2(g) 5=^ 2 NHt(g) at this temperature. [H2] = 0.10 mol L_1, [NJ = 1.1 mol L"1, [NHJ = 3.6 X 10"-mol L'1
In the text, the equation G=G+RTIn(Q) was derived for gaseous reactions where the quantities in Q were expressed in units of pressure. We also can use units of mol/L for the quantities in Q, specifical.ly for aqueous reactions. With this in mind, consider the reaction HF(aq)H+(aq)+F-(aq) for which Ka = 7.2 104 at 25C. Calculate G for the reaction under the following conditions at 25C. a. [HF] = [H+] = [F] = 1.0 M b. [HF] = 0.98 M, [H+] = [F] = 2.7 102M c. [HF] = [H+] = [F] = 1.0 105 M d. [HF] = [F] = 0.27 M, [H+] = 7.2 104M e. [HF] = 0.52 M, [F] = 0.67 M, [H+] = 1.0 103M Based on the calculated G values, in what direction will the reaction shift to reach equilibrium for each of the five sets of conditions?
At mom temperature, the equilibrium constant (Kw) for the self-ionization of water is 1.001014. Using this information, calculate the standard free energy change for the aqueous reaction of hydrogen ion with hydroxide ion to produce water. (Hint: The reaction is the reverse of the self-ionization reaction.)
Adenosine triphosphate, ATP, is used as a free-energy source by biological cells. (See the essay on page 624.) ATP hydrolyzes in the presence of enzymes to give ADP: ATP(aq)+H2O(l)ADP(aq)+H2PO4(aq);G=30.5kJ/molat25C Consider a hypothetical biochemical reaction of molecule A to give molecule B: A(aq)B(aq);G=+15.0kJ/molat25C Calculate the ratio [B]/[A] at 25C at equilibrium. Now consider this reaction coupled to the reaction for the hydrolysis of ATP: A(aq)+ATP(aq)+H2O(l)B(aq)+ADP(aq)+H2PO4(aq) If a cell maintains a high ratio of ATP to ADP and H2PO4 by continuously making ATP, the conversion of A to B can be made highly spontaneous. A characteristic value of this ratio is [ATP][ADP][H2PO4]=500 Calculate the ratio [B][A] in this case and compare it with the uncoupled reaction. Compared with the uncoupled reaction, how much larger is this ratio when coupled to the hydrolysis of ATP?
A gaseous material XY(g) dissociates to some extent to produce X(g) and Y(g): XY(g)X(g)+Y(g) A 2.00-g sample of XY (molar mass = 165 g/mol) is placed in a container with a movable piston at 25C. The pressure is held constant at 0.967 atm. As XY begins to dissociate, the piston moves until 35.0 mole percent of the original XY has dissociated and then remains at a constant position. Assuming ideal behavior, calculate the density of the gas in the container after the piston has stopped moving, and determine the value of K for this reaction of 25C.
. The reaction PCl3(l)+Cl2(g)PCl5(s)liberates 124 kJ of energy per mole of PCl3reacted. Will an increase in temperature shift the equilibrium position toward products or toward reactants?
. Suppose that for the reaction PCl5(g)PCl3(g)+Cl2(g)it is determined, at a particular temperature. that the equilibrium concentrations are [PCl5(g)]=0.0711M,[PCl3(g)]=0.0302M, and [Cl2(g)]=0.0491M. Calculate the value of K for he reaction at this temperature.
Because carbonic acid undergoes a second ionization, the student in Exercise 12.39 is concerned that the hydrogen ion concentration she calculated is not correct. She looks up the equilibrium constant for the reaction HCO,-(aq) «=* H+(aq) + COf'(aq) Upon finding that the equilibrium constant for this reaction is 4.8 X 10“H, she decides that her answer in Exercise 12.39 is correct. Explain her reasoning. A student is simulating the carbonic acid—hydrogen carbonate equilibrium in a lake: H,CO,(aq) 5=6 H+(aq) + HCO,'(aq) K = 4.4 X 10'7She starts with 0.1000 A1 carbonic acid. W hat are the concentrations of all species at equilibrium?