** Below is the image of my code so far, but it still needs work** * This program asks the user to enter an integer from 3 to 9 * and prints a pattern of numbers based on that number. * For example, given the number 4 as input, the output would be: * * 1* * 21* * 321* * 4321* * 321* * 21* * 1* * * Print a newline between the prompt and the beginning of the stars. * Note that no input validation is required.
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** Below is the image of my code so far, but it still needs work**
* This
* and prints a pattern of numbers based on that number.
* For example, given the number 4 as input, the output would be:
*
* 1*
* 21*
* 321*
* 4321*
* 321*
* 21*
* 1*
*
* Print a newline between the prompt and the beginning of the stars.
* Note that no input validation is required.
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- This is the question - Write a program that inserts parentheses, a space, and a dash into a string of 10 user-entered numbers to format it as a phone number. For example, 5153458912 becomes (515) 345-8912. If the user does not enter exactly 10 digits, display an error message. Continue to accept user input until the user enters 999. This is the code I have - However it isn't seeming to accept my output. It doesn't like what I have for some reason - import java.util.*; public class PhoneNumberFormat { public static void main(String[] args) { // Write your code here //Create an instance of Scanner class Scanner keyboard=new Scanner(System.in); //declare string data type variables String phoneNumber= ""; String formattedPhoneNumber=""; /*Run the loop infinitely until user enters 999 to exit from program*/ while(true) { System.out.println("Enter phone number: "); phoneNumber=keyboard.nextLine(); //exit…This Code print the first occurrences of x, Modify the code to print the last occurrences of x and print how many times it exists? ( with explanation for each line if possible) many thanks.C++ In this task, you are required to write a code that converts an Octal number into its equivalent Decimal value or vice versa. The user first selects the conversion choice by inserting 1 or 2. Choice 1 is followed by inserting an Octal integer and getting its Decimal equivalent value as an output. Choice 2 requires inserting a Decimal integer and prints out its Octal equivalent. The Octal numeral system, is the base-8 number system, and uses the digits 0 to 7, that is to say 10 octal represents 8 Decimal and 100 octal represents 64 Decimal. Convertion from an Octal integer into Decimal In the Decimal system, each number is the digit multiplied by 10 to the power of its location (starting from 0). For example: 74 decimal = 7 x 10^1 + 4 x 10^0 1252 decimal = 1 x 10^3 + 2 x 10^2 + 5 x 10^1 + 2 x 10^0 each number is the digit multiplied by 8 to the power of its location (starting from 0). For example: 112 octal = 1 x 8^2 + 1 x 8^1 + 2 x 8^0 Converting an Octal integer into…
- Q12,. A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers. Given a string s, return true if it is a palindrome, or false otherwise. Example 1: Input: s = "A man, a plan, a canal: Panama" Output: true Explanation: "amanaplanacanalpanama" is a palindrome. Example 2: Input: s = "race a car" Output: false Explanation: "raceacar" is not a palindrome..Implement the following: 1) Use a loop to print all the numbers of multiples of 6 and multiples of 7 from 166 to 377 inclusive. 2) Use a loop to print all the numbers of multiples of 6 and multiples of 7 from 377 to 166 inclusive. Make sure to precisely match the output format below. Write your code in the ANSWER area provided below (must include comments if using code is not covered in the course). Example Output 168, 210, 252, 294, 336, 336, 294, 252, 210, 168,When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This can be done by normalizing to values between 0 and 1, or throwing away outliers. For this program, adjust the values by subtracting the smallest value from all the values. The input begins with an integer indicating the number of integers that follow. Ex: If the input is: 5 30 50 10 70 65 the output is: 20 40 0 60 55 The 5 indicates that there are five values in the list, namely 30, 50, 10, 70, and 65. 10 is the smallest value in the list, so is subtracted from each value in the list. For coding simplicity, follow every output value by a space, including the last one. 272772.1571588
- Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1 this is what i have n = int(input())count = 1while n != 1: if count%10==0: print(n,'\t') else: print(n, end='\t') if n%2==0: n = int(n/2) else: n = int(n*3 + 1) count = count + 1 print(n) the output is correct but theres whitespaces that arnt neededGiven a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1 python please explain so i understandGiven a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1 I can't figure out where the new line space is supposed to be
- Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:System.out.print(n + "\t"); Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1 (NEED HELP IN JAVA PLEASE)Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:System.out.print(n + "\t"); Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1