13 QUESTION 2Below shows the results from comparing the total out-of-pocket costs of prescription drugs ("TOTAL RX-SELF/FAMILY AMT 14), the totalout-of-pocket costs of patient's office visits ("ALL OFFICÉ VISITS-SELF/FAMILÝ AMT 14), and age between people with insurance ("Insured") and those without insurance ("Uninsured"). Mark True or False. (alpha=0.05)UninsaredMean (SD)InsuredMean (SD)VarlableP-valueTOTAL RX-SELFFAMILY AMT 14163535732 (1231)271.19 (13.86)0242ALL OFFICE VISITS- SELFFAMILY AMT 141622303.20 (622 27)284.98 (639.69)0.619AGE AS OF 123/14 (EDITED IMPUTED)38.08 (12.32)391338.72 (14.64)0.138There is statistically significant evidence that the uninsured and the insured pay different amounts for prescription drugs.O TrueO False

Solution There exists a statistical significance when the null hypothesis is rejected and the null…

Below shows the results from comparing the total out-of-pocket costs of prescription drugs (TOTAL RX-SELFIFAMILY AMT 14), the total out-of-pocket costs of patient's office visits (ALL OFFICE VISITS-SELFIFAMILY AMT 14, and age between people with insurance Insured") and those without insurance ("Uninsured"). Mark True or False. (alpha=0.05) Usisered Mean (SD) Insered Mean SD) Vartable Pralee TOTAL RX-SELFFAMILY AMT 14 357.32 (12.31) 271.19( 1635 0242 ALL OFFICE VISITS-SELFFAMILY AMT 14 1622 301.20 (62227 284.9 (69) 0619 AGE AS OF 12/3/14 (EDITED IMPUTED) 38.08 (12.32) 3913 38.72(1464) There is statistically significant evidence that the uninsured and the insured pay diferent amounts for prescription drugs. O True O False

Below shows the results from comparing the total out-of-pocket costs of prescription drugs (TOTAL RX-SELFIFAMILY AMT 14), the total out-of-pocket costs of patient's office visits (ALL OFFICE VISITS-SELFIFAMILY AMT 14, and age between people with insurance Insured") and those without insurance ("Uninsured"). Mark True or False. (alpha=0.05) Usisered Mean (SD) Insered Mean SD) Vartable Pralee TOTAL RX-SELFFAMILY AMT 14 357.32 (12.31) 271.19( 1635 0242 ALL OFFICE VISITS-SELFFAMILY AMT 14 1622 301.20 (62227 284.9 (69) 0619 AGE AS OF 12/3/14 (EDITED IMPUTED) 38.08 (12.32) 3913 38.72(1464) There is statistically significant evidence that the uninsured and the insured pay diferent amounts for prescription drugs. O True O False

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter1: Equations And Graphs

Section: Chapter Questions

Problem 10T: Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s...

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Repeat Example 5 when microphone A receives the sound 4 seconds before microphone B.
Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s pole vault height has fallen below the value predicted by the regression line in Example 2. This might have occurred because when the pole vault was a new event there was much room for improvement in vaulters’ performances, whereas now even the best training can produce only incremental advances. Let’s see whether concentrating on more recent results gives a better predictor of future records. (a) Use the data in Table 2 (page 176) to complete the table of winning pole vault heights shown in the margin. (Note that we are using x=0 to correspond to the year 1972, where this restricted data set begins.) (b) Find the regression line for the data in part ‚(a). (c) Plot the data and the regression line on the same axes. Does the regression line seem to provide a good model for the data? (d) What does the regression line predict as the winning pole vault height for the 2012 Olympics? Compare this predicted value to the actual 2012 winning height of 5.97 m, as described on page 177. Has this new regression line provided a better prediction than the line in Example 2?
QUESTION 3 The Research Unit for Cecilion Supermart conducted an experiment to estimate the strength of thecarrier bag from the starch-based biofilms made from two different jicamas (sengkuang) of type Aand type B. However, the researcher claims that jicama type A produces more strength comparedto type B. To support this claim, 10kg weight item was put into 100 carrier bags made from jicamatype A and 200 carrier bags made from jicama type B were randomly selected. As a result, 8 bagsfrom jicama type A burst while 12 bags from jicama type B burst. Calculate a 95% confidenceinterval for the difference in true proportion of the carrier bags which burst between jicama type Aand type B. Give comment on the parameter estimate.
Question 2: Assume that the risk-free rate, RF, is currently 8%, the market return, RM, is 12%, and asset A has a beta, of 1.10. (could be done on word document or excel). Assume that as a result of recent events, investors have become more risk averse, causing the market return to rise by 2%, to be14%. Ignoring the shift in part c, draw the new SML on the same set of axes that you used before, and calculate and show the new required return for asset A. From the previous changes, what conclusions can be drawn about the impact of (1) decreased inflationary expectations and (2) increased risk aversion on the required returns of risky assets?
QUESTION 25 A clinical trial is being conducted in order to determine the efficacy of a new drug used to treat Rheumatoid arthritis. The efficacy of the medication will not only be determined by the physical improvement of symptoms but also by using a blood test to examine the concentration C-reactive protein (an inflammatory marker) in an individual’s blood. If the researcher wants a margin of error for the level of C-reactive protein to be less than or equal to 3.0 mg/dL, and if the standard deviation for C-reactive protein concentrations among arthritis patients was previously documented at 8 mg/dL, how many patients should be recruited for each group in the study assuming a 95% confidence interval will be used to quantify the mean differences between the control group and the treatment group? nfor the treatment group = 112; n for the control group = 111 nfor the treatment group = 56; n for the control group = 57 nfor the treatment group = 55; n…
Question 7 Consider a cohort study to compare the mortality rate of myocardial infarction (MI) in men with sedentary work (exposed group) to men with physically active work (unexposed). If in the exposed, there were 36,000 person (man) years of observation and 126 deaths whereas the unexposed had 24,000 man-years of observation and 44 deaths. Compute the following a) Mortality rate in each cohort? b) What is the relative risk of dying, comparing these 2 groups? c) What is the attributable risk of sedentary work? d) What is the attributable benefit of physical activity? e) If we assume that MI is associated with the mortality in this cohort (causality), what proportion of the disease in the higher group is potentially preventable?
Question 9b . Describe the relationship displayed in the scatterplot (Using DUFS)
question 1 Researchers have suggested that sleep apnoea (the tendency to occasionally stop breathing when asleep) may worsen the effects of allergen-induced asthma. To investigate this possibility, Johnson and colleagues (2015), compared two groups of rats, a normal healthy non-allergic group, and a second group that were mildly allergic to ovalbumin. They subjected these rats to one of two treatments – 1) a 10-minute period of induced hypoxia (oxygen down to 10% of the air), representing the kind of temporary hypoxia that sufferers of sleep apnoea may be subjected to, and 2) a control (normal air) group. They then compared the respiratory function of both groups in these two treatments by using a two-factor ANOVA. (Questions are on the next page). Source df F P Rat type 1 21.88 <0.0001 Oxygen treatment 1 141.13 <0.0001 Rat type x oxygen treatment 1 15.68 <0.001 Residual 36 What are the 3 null hypotheses are…
QUESTION 11 Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the previous 6 months, in a sample of 115 new-car buyers, 46 have traded in their old car. To determine (at the 10% level of significance) whether the proportion of new-car buyers that trade in their old car has statistically significantly decreased; what is the critical value? (please round your answer to 2 decimal places)
Question # 1 A well-known multinational FMCG produces more than fifty products and sells them in the market. Out of fifty products one is mineral water for drinking purpose and supplies different size pack bottles in the market. Product manager observed that, during hot days the sale of water is more as compared to the normal days. He started the collection of data of weekly sale of water and the average weekly temperature. Product manager was interested in developing a relationship between sales and temperature; therefore, he discussed and shared the following data with you. sales 75 77 69 63 79 80 77 70 73 87 72 73 80 80 69 84 77 72 74 81 temperature 32 36 31 31 34 29 32 35 28 31 30 31 29 35 36 28 32 33 32 33 Sale is in thousand liters and temperature is in degree Celsius. Data…
QUESTION 6 A new starch polymer foam with high shock absorbent properties is expected to perform better thanthe old foam which can withstand a maximum impact of 1.56 Joule (J). A simple destructive testto quantify shock absorption ability of the new foam is conducted. Table 5 shows the impact energyabsorbed (in J) that the new foam can withstand for each test.Table 51.61 1.5 1.65 1.7 1.4 1.59 1.65 1.5Does the recorded data suggests that the new foam performs better than the old foam? Use 2.5%level of significance.
QUESTION 12 Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the previous 6 months, in a sample of 115 new-car buyers, 46 have traded in their old car. To determine (at the 10% level of significance) whether the proportion of new-car buyers that trade in their old car has statistically significantly decreased, what can you conclude concerning the null hypothesis? Reject the null hypothesis Fail to reject the null hypothesis