BINARY SEARCH: PYTHON CODE #Binary Search Algorithm def BinarySearch(sampleList, value): low = 1 high = len(samplelist) j = 0 while(low <= high) and (j == 0): mid = int((low + high)/2) if (value == sampleList[mid]): j = mid break elif (value < sampleList [mid]): high = mid - 1 else: %3D low = mid + 1 return j
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- java The search method accepts ArrayList of Strings and String find. The method returns a String. It will look for an element within ArrayList that contains value of find if it finds it, methods needs to return whole Element value. if an instance of find doesn't exist return:"search failed" Example: search(["one apple","two orange","four banana"],"four") returns: "four banana" ("four banana" contains "four" so method returns "four banana")please update generateRandoms, letterToGrades, sumBetween, countCharacters //A6Utilities.java import java.io.IOException;import java.nio.file.Files;import java.nio.file.Paths;import java.security.SecureRandom;import java.util.List;import java.util.TreeMap;import java.util.function.Function;import java.util.stream.Collectors;public class A6Utilities {/*** Returns the corresponding letter grade. Don't modify this method, simply use it when converting single* grades to their equivalent letter grade** @param grade the integer grade to convert* @return the letter grade equivalent to the integer grade*/private static char letterGrade(final int grade) {if (grade < 0) return '?';else if (grade < 60) return 'F';else if (grade < 70) return 'D';else if (grade < 80) return 'C';else if (grade < 90) return 'B';else if (grade <= 100) return 'A';else return '?';}/*** The method uses Java Streams only. Don't use any looping structures, conditional statements are OK (IF, TERNARY,…public class CustomLinkedList { public static int findMax(IntNode headObj) { /* Type your code here */ } public static void main(String[] args) { IntNode headObj; IntNode currObj; IntNode lastObj; int i; int max; // Create head node headObj = new IntNode(-1); lastObj = headObj; // Add nodes to the list for (i = 0; i < 20; ++i) { currObj = new IntNode(i); lastObj.insertAfter(currObj); lastObj = currObj; } max = findMax(headObj); System.out.println(max); }}
- Write a complete Java program that provides two methods named orderList(list) and lastIndexOf(list, targetValue). The first method should sort the elements ascendingly from a-z using Selection Sort Algorithm. The second method should return the last index at which a predetermined target value occurs in the list using Binary Search Algorithm. The method should return -1 if the target value is not found. List size, elements and target value should be read from the user.An array may contain multiple duplicate values, as shown below. In order to design an algorithm with the best average performance to remove all duplicate values, which of the following data structures should be used? [34, 45, 60, 45, 30, 24, 34, 60] Question 47 options: List Priority queue Hash table Stackin java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…
- IMPLEMENTATION OF BINARY SEARCH TREESDevC++ Code (paste the link to browser):https://paste.ofcode.org/K3uqRBy7z65V4exvcrShgF Focus on the main (driver program) or int main (), just make a MENU DRIVEN program by relating to the program template. Laboratory Task 8:Create a menu-driven program that will properly insert a new element to the Binary Search Tree (BST). The options of the program are the following:1. Insert Element2. Display Binary Search Tree3. Exit Option (1) inserts a new element to its proper location in the BST. Take note of the following properties of the Binary Search Tree:The left subtree of a node contains only nodes with elements lesser than the element. The right subtree of a node contains only nodes with elements greater than the node s element.The left and right subtree each must also be a BST. There must be noduplicate nodes.Option (2) displays all the elements in the BST in proper order.Option (3) exits the program.(Generic binary search) Implement the following method using binary search. public static > int binarySearch(E[] list, E key)Data Structure and algorithms ( in Java ) Please solve it urgent basis: Make a programe in Java with complete comments detail and attach outputs image: Question is inside the image also: a). Write a function to insert elements in the sorted manner in the linked list. This means that the elements of the list will always be in ascending order, whenever you insert the data. For example, After calling insert method with the given data your list should be as follows: Insert 50 List:- 50 Insert 40 List:- 40 50 Insert 25 List:- 25 40 50 Insert 35 List:- 25 35 40 50 Insert 40 List:- 25 35 40 40 50 Insert 70 List:- 25 35 40 50 70 b). Write a program…
- When compared to alternative data structures like a linked list or an array, how are binary search trees better?import java.util.ArrayList;import java.util.Arrays; public class PS07A{/*** Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical…Python Multiple Choice Explain: For an ordered list of 11 items, how many comparisons will a linear search need before it knows that a value is NOT in the list? a. 11 b. 12 c. 6 d. 4