java The search method accepts ArrayList of Strings and String find. The method returns a String. It will look for an element within ArrayList that contains value of find if it finds it, methods needs to return whole Element value. if an instance of find doesn't exist return:"search failed" Example: search(["one apple","two orange","four banana"],"four") returns: "four banana" ("four banana" contains "four" so method returns "four banana")

Project Description: In this project you implement an ArrayStack ADT and use the stack for implementing the following methods: a) Reverse an array of Words: Accept an array of words as input parameter and return an array of words in reverse order. Use the method signature: public static String[] reverse Words (String[] wordList) Example Input: Bird Cat Dog Elephant Output: Elephant Dog Cat Bird

Binary Search Java

Create an array and store 10 multiples of 5 and print it out. Use for loop to generate the multiples and then print them out using a second for loop.   5 10 15 20 25 30 35 40 45 50   Note: You cannot get any credit if you don't use array or for loop.   JAVA CODE   class Main {public static void main(String[] args) {}}

Computer Science JAVA #7 - program that reads the file named randomPeople.txt sort all the names alphabetically by last name write all the unique names to a file named namesList.txt , there should be no repeats

X42: frontPiece Given an int array of any length, return a new array of its first 2 elements. If the array is smaller than length 2, use whatever elements are present. Examples: frontPiece ({1, 2, 3}) -> {1, 2} frontPiece ({1, 2}) -> {1, 2} Your Answer: Feedback Your feedback will appear here when you check 1 public int[] frontPiece(int[] nums) 2 { your answer. 3 4 }

param data * @return true if all items of the array are positive (more than 0), false otherwise. * return false if the array is null. */ public boolean allPositives(int[] data) without using functions

%matplotlib inlineimport numpy as npfrom matplotlib import pyplot as pltimport math xs = np.array([0.        , 0.01010101, 0.02020202, 0.03030303, 0.04040404,        0.05050505, 0.06060606, 0.07070707, 0.08080808, 0.09090909,        0.1010101 , 0.11111111, 0.12121212, 0.13131313, 0.14141414,        0.15151515, 0.16161616, 0.17171717, 0.18181818, 0.19191919,        0.2020202 , 0.21212121, 0.22222222, 0.23232323, 0.24242424,        0.25252525, 0.26262626, 0.27272727, 0.28282828, 0.29292929,        0.3030303 , 0.31313131, 0.32323232, 0.33333333, 0.34343434,        0.35353535, 0.36363636, 0.37373737, 0.38383838, 0.39393939,        0.4040404 , 0.41414141, 0.42424242, 0.43434343, 0.44444444,        0.45454545, 0.46464646, 0.47474747, 0.48484848, 0.49494949,        0.50505051, 0.51515152, 0.52525253, 0.53535354, 0.54545455,        0.55555556, 0.56565657, 0.57575758, 0.58585859, 0.5959596 ,        0.60606061, 0.61616162, 0.62626263, 0.63636364, 0.64646465,        0.65656566, 0.66666667,…

Complete the method endsInFive that takes as arguments a 2D-array of integers and an integer value that represents a column index in the array. endsInFive returns the number of values in the column that end in 5. It is possible that the array is ragged, meaning that the number of columns in each row is different. For example, 2 is returned if the following 2D-array is passed as the first argument of endsInFive and the integer 3 as the second argument (the values 25 and 115 end in five at column index 3).

For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }