Binary tree is given. Per node is assumed as cam and it takes care of its other nodes. C++ code: Example 1: Input: root = [0,0,null,0,0] Output: 1
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- C++ Consider the binary search tree in the figure below. The numbers simply label the nodes so that you can reference them; they do not indicate the contents of the nodes. The answer to this question is the node position to the left of the node (the numbers 1-31). Beginning with an empty binary search tree, consider the binary search tree that is formed when you insert the following values in the order given: B, T, E, A, N, W, J At what position is N?in c++ Assume that you have a binary search tree. Write a function that counts the number ofelements in the tree that are less than 15 and prints the result. You write only the func-tion, you do not need to test it.in c++, write a function to find the height of a specific node in a Binary Search Tree.
- C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) {…Complete the following problem in C++. Build a binary search tree using the following data shown below. Show the root node value, the left & right pointers value, the subscripts order and balance factor value all in a table chart format. Given data: Data = 5, 10, 4, 2, 16, 7, 1 20 15, 3 in this order, no presorting.Write a recursive function called "GetParent" in Binary Search Tree of the given node. You can take as many arugments as you like. Use the following structure defination. struct TNode{ char NodeName[10]; TNode *LeftT, *RightT; } root; use c++
- Use c++ 1. A Red-Black tree is said to be beautiful if all nodes in the alternate levels of the tree are of the same color. Write a program to check whether a Red-Black tree created from the given input is beautiful or not. Your program should include the following functions. • INSERTREDBLACK (struct node* root, key): Inserts a new node with the 'key' into the tree. • CHECKBEAUTIFUL (struct node* root): Checks whether the given tree is beautiful or not. Input format: Output format: • The output will be 1 if the Red-Black tree is beautiful else -1. Sample Input 1: 9 12 • The first line of input will be an integer 'n' which is the number of nodes in the tree. • After which 'n' integer inputs will be given subsequently which will be the keys of nodes of the tree. The keys are unique and values are in the range [1,1000]. 8 25 3 5 27 22 32 9 Sample Output 1: 1C++, Write a recursion function that counts the positive elements multiple of 5 in a binary search tree and counts the elements less than 0 and multiple of 2, then returns the two counts multiplied to the main.Note that you have to write only one function and you can add parameters to the function as neededC++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) { if(p->left == NULL){ node* newLeft =…
- Modify the given code to accept float instead of int as a coefficient in C LANGUAGE: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 =…C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* findNewRoot(node* curr) { if(curr->left == NULL) { return curr; } return findNewRoot(curr->left); } bool remove(int num) { bool isPresent = search(num); if(isPresent){ bool rem = false; int numOfChild; node* realRoot = search_node(root,num); if(realRoot->left == NULL && realRoot->right == NULL) { numOfChild = 0; } else if((realRoot->left != NULL && realRoot->right == NULL) || (realRoot->left == NULL && realRoot->right != NULL) ) { numOfChild = 1; } else if(realRoot->left != NULL && realRoot->right != NULL) { numOfChild = 2; } if(numOfChild == 0) { bool leadRoot = false; if(realRoot…C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) int childCount(node* p) { bool Cright = false; bool Cleft = false; if(p->right != NULL){ Cright = true; } if(p->left != NULL){ Cleft = true; } if(Cleft == true && Cright== true){ return 2; } if(Cright){ return 1; } if(Cleft){ return -1; } return 0; } int set(node* p, int e) { int elem = p->element; p->element = e; return elem; } node* addSibling(node* p, int e) { node* P = p->parent; if(P != NULL){ if(sibling(p) == NULL){…