Block 1 (16 kg) is located on the surface of a table. A rope pulls on block 1 with a horizontal tension of 113 N to the right and a vertical tension of 150 N upward. The coefficient of kinetic friction between the block and the surface equals 0.1. On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E =  i +  j N Tension force on block 1 by Rope T1R =  i +  j N Normal force on block 1 by Surface N1S =  i +  j N Frictional force on block 1 by Surface f1S =  i +  j N   Tries 0/2   What is the acceleration a of block 1? a =  i +  j m/s2

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter5: Newton's Law Of Motion
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THERE IS NO DIAGRAM IN THE PROBLEM IT IS NOT INCOMPLETE***

Block 1 (16 kg) is located on the surface of a table. A rope pulls on block 1 with a horizontal tension of 113 N to the right and a vertical tension of 150 N upward. The coefficient of kinetic friction between the block and the surface equals 0.1.
On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component.

FORCES on BLOCK 1
Weight force on block 1 by Earth
W1E =  i +  j N

Tension force on block 1 by Rope
T1R =  i +  j N

Normal force on block 1 by Surface
N1S =  i +  j N

Frictional force on block 1 by Surface
f1S =  i +  j N

  Tries 0/2  



What is the acceleration a of block 1?
a =  i +  j m/s2

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