Block 1 (2 kg) is setting on the floor of an elevator. A hand pushes vertically down on block 1 with a force of 26.0 N. The elevator is moving downward with an increasing speed and the magnitude of the acceleration is 7 m/s2. On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. NET force on Block 1 Fnet1 = i + j N FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Normal force on block 1 by Hand N1H = i + j N

Block 1 (2 kg) is setting on the floor of an elevator. A hand pushes vertically down on block 1 with a force of 26.0 N. The elevator is moving downward with an increasing speed and the magnitude of the acceleration is 7 m/s2. On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. NET force on Block 1 Fnet1 = i + j N FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Normal force on block 1 by Hand N1H = i + j N

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section: Chapter Questions

Problem 80A

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