Br Br2 CH3 CH3 H3C° CH2Cl2 H3C Br Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br: :Br: CH3 H3C H3C CH3 Br:

Organic Chemistry
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ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter17: Alcohols And Phenols
Section17.SE: Something Extra
Problem 71AP: A problem often encountered in the oxidation of primary alcohols to acids is that esters are...
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Br
Brz
CH3
CH3
H3C
CH2CI2
H3C
Br
Electrophilic addition of bromine, Br2; to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion.
The reaction occurs in an anhydrous solvent such as CH,Cl).
In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes,
the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
Br:
:Br:
.CH3
H3C
H3C
CH3
Br:
Transcribed Image Text:Br Brz CH3 CH3 H3C CH2CI2 H3C Br Electrophilic addition of bromine, Br2; to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl). In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br: :Br: .CH3 H3C H3C CH3 Br:
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