-bromo-1-methylcyclopentane is being reacted with sodium ethoxide in diethyl ether Ethoxide will remove a proton from one of the carbons alpha to the carbon bonded to bromine. The electron pair from the carbon-hydrogen bond will move toward the 1 carbon to form a new pi bond. This will push off the bromine, which will leave with its electron pair to form a bromide leaving group. This will form the product 1-methylcyclopentene and sodium bromide as byproduct. So, is this reaction following an E1 or E2 mechanism? Write out the rate law for this reaction. Draw a reaction coordinate diagram for this reaction.

-bromo-1-methylcyclopentane is being reacted with sodium ethoxide in diethyl ether Ethoxide will remove a proton from one of the carbons alpha to the carbon bonded to bromine. The electron pair from the carbon-hydrogen bond will move toward the 1 carbon to form a new pi bond. This will push off the bromine, which will leave with its electron pair to form a bromide leaving group. This will form the product 1-methylcyclopentene and sodium bromide as byproduct. So, is this reaction following an E1 or E2 mechanism? Write out the rate law for this reaction. Draw a reaction coordinate diagram for this reaction.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter25: Enolate & Enol Nucleophiles

Section: Chapter Questions

Problem 11CTQ

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